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irina [24]
2 years ago
5

Has anyone done Exponential Growth and Decay (in mathematical models with application A) on sos or odysseware and gotten a prefe

ct score?? Pls help!
I need help on the whole assignmnet but particularly this question..

Mathematics
1 answer:
Lilit [14]2 years ago
4 0

Answer:

1) 62.5

2) 50

3) 75

4) 100

Step-by-step explanation:

1)

Because it has a half-life of 25 days, half of it will decay after 25 days.

After 25*4=100 days, there will be (1/2)^{4}=1/2^{4}=1/16 of it left.

So, 1000/16=\boxed{62.5}.

2)

Because it has a half-life of 25 days, half of it will decay after 25 days.

After 25*3=75 days, there will be (1/2)^{3}=1/2^{3}=1/8 of it left.

So, 400/8=\boxed{50}

3)

Because it has a half-life of 25 days, half of it will decay after 25 days.

After 25*2=50 days, there will be (1/2)^2=1/2^{2}=1/4 of it left.

So, 300/4=\boxed{75}.

4)

The only answer left is \boxed{100} grams. You can solve it the same way you solved the previous steps.

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Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an
Leya [2.2K]
Parameterize the lateral face T_1 of the cylinder by

\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v

where 0\le u\le2\pi and 0\le v\le3, and parameterize the disks T_2,T_3 as

\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)
\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)

where 0\le r\le2 and 0\le\theta\le2\pi.

The integral along the surface of the cylinder (with outward/positive orientation) is then

\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS
=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr
=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr
=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr
=136\pi
7 0
3 years ago
What is the first step in solving the equation: 3(x+2) = 12?
yanalaym [24]

Answer:

Divide by 3 on both sides.

Step-by-step explanation:

Original Expression: 3(x+2) = 12

Divide by 3 on both sides: x+2 = 4

Subtract 2 from both sides: x=2

Let me know if this helps!

4 0
2 years ago
What is the total when the product of 57 and .22 is added to 7 percent of 57
11111nata11111 [884]
I believe the total is 16.53. First I took 7% of 57 is 3.99. Then multiplying 57 by 0.22 and adding that to 3.99 which is 16.53
6 0
3 years ago
£750 is divided between Bridget, Caroline & Sarah so that Bridget gets twice as much as Caroline, and Caroline gets three ti
Sladkaya [172]

Answer: £225

Step-by-step explanation:

Let Sarah's amount be represented by x.

Since Caroline gets three times as much as Sarah, Caroline will get: 3x

Bridget gets twice as much as Caroline, therefore Bridget will get: 2 × 3x = 6x

Sarah = x

Caroline = 3x

Bridget = 6x

Total = x + 3x + 6x = 10x

Caroline's faction is 3/10. We then multiply the fraction by £750. This will be:

= 3/10 × £750

= 0.3 × £750

= £225

Caroline will get £225

4 0
3 years ago
Please help answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!! ASAP !!!!!!!
storchak [24]

Answer:

16.9°

Step-by-step explanation:

tan x = 1.7/5.6

tan^-1 x = 16.9°

7 0
3 years ago
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