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densk [106]
3 years ago
13

Find the average of the ff: 1. 10, 12, 16, 17,20 2. 0, 3,6,9

Mathematics
1 answer:
Kryger [21]3 years ago
6 0

Answer:

1) 15

2) 4.5

Step-by-step explanation:

1 ) 10, 12, 16, 17,20

Average = \frac{\text{Sum of all observations}}{\text{Total no. of observations}}

Average = \frac{10+12+16+17+20}{5}

Average = 15

2) 0, 3,6,9

Average = \frac{\text{Sum of all observations}}{\text{Total no. of observations}}

Average = \frac{0+3+6+9}{4}

Average = 4.5

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A worker on a scaffolding 75 ft above the ground needs to lift a 500 lb bucket of cement from the ground to a point 30 ft above
Lemur [1.5K]

Answer:

W = 15900 ft.lb

Step-by-step explanation:

From the given information.

Consider y to be the distance from the ground towards the bucket of the cement.

At height y, suppose the bucket is lifted by Δy.

Then, the workdone can be = 500Δy + 0.5(75 - y) Δy

where;

The bucket of the cement =  500Δy

The remaining of the rope =  0.5(75 - y) Δy

However; the workdone (W) can be calculated as:

W = \int^{30}_{0} \ 500 \ dy + \int^{30}_{0} \ 0.5 (75-y ) \ dy

W = 500 \times 30 + 0.5 \bigg(75 \times 30 - \dfrac{1}{2} \times 30^2 \bigg )

W = 15000 + 0.5 ( 2250 - 450)

W = 15000 + 900

W = 15900 ft.lb

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3 years ago
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MrRissso [65]

Answer:

Step-by-step explanation:

1. the solution is the fourth one

2. the solution is the first one

3 0
3 years ago
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What is -17 + 12 + 15?​
madam [21]

Answer:

10

Step-by-step explanation:

6 0
3 years ago
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Please help me with this. simplify and show all your work.
iren2701 [21]
Let's take this variable by variable. z to the power of 4 over z to the power of one would equal z to the power of 3. At this point, there is no longer a z variable in the denominator.
X to the power of 2 over x to the power of 1 would equal x. At this point there is also no x variable in the denominator.
Y to the power of 1 over y to the power of 2 would equal (1/y). At this point, there is no y in the NUMERATOR. 

Final Answer: \frac{ z^{3}x }{y}

5 0
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