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shepuryov [24]
3 years ago
6

PLEASE HELP ASAP!!!! simplify this expression y=0.03y

Mathematics
1 answer:
Elanso [62]3 years ago
6 0

Answer:

103y/100

Step-by-step explanation:

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How to find inflection points from first derivative
Mekhanik [1.2K]

Answer:

For finding the inflection points you'll have to put the first derivative equal to zero and solve for x. After you've done that, you can plug in the x you've just found into the original function and find also the y, so you'll find the ordered pair (x,y) of the inflection point(s).

7 0
3 years ago
Major help I would highly appreciate it:(
Elena L [17]

Answer:

  9

Step-by-step explanation:

The function's y-intercept is the value for x=0.

  h(0) = 0.5(0 +4)² +1

  = 0.5(16) +1

  = 8 +1

  h(0) = 9

The function's y-intercept is 9.

3 0
4 years ago
Dado dos ángulos complementarios, uno mide (2x + 10) y el otro (x + 20),
rusak2 [61]

Answer:

El valor de <em>x</em> es igual a 20 o <em>x</em> = 20.

Step-by-step explanation:

Lo primero que se debe saber es que <em>dos ángulos complementarios suman un ángulo recto o 90º</em>.

Supongamos que el valor de un ángulo \\ \alpha y un ángulo \\ \beta valen:

\\ \alpha = 2x + 10 [1]

\\ \beta = x + 20 [2]

Como la suma de  \\ \alpha + \beta = 90 [3]

Entonces

\\ \alpha + \beta = (2x + 10) + (x + 20) = 90

Sumamos los factores comunes entre si:

\\ (2x + x) + (10 + 20) = 90

Para la primera expresión debemos recordar que se suman sólo los coeficientes. Así:

\\ (2 + 1)x + (10 + 20) = 90

\\ 3x + 30 = 90

Para despejar la incógnita <em>x</em>, debemos tener en cuenta que <em>una igualdad no se altera si se suma, se resta, se multiplica o divide un mismo valor a cada lado de ella</em>. Por esta razón, para despejar 3x, lo primero que podemos hacer es sumar -30 a cada lado de la expresión (lo que es igual a restar 30 a cada lado de la misma). Así tenemos:

\\ 3x + 30 - 30 = 90 - 30

\\ 3x + 0 = 90 - 30

\\ 3x = 60

Ahora dividimos cada miembro de la igualdad entre 3 (o multiplicamos cada lado de la igualdad por \\ \frac{1}{3} ):

\\ \frac{3}{3}x = \frac{60}{3}

Como sabemos que:

\\ \frac{3}{3} = 1

Entonces:

\\ 1*x = \frac{60}{3}

\\ x = \frac{60}{3}

\\ x = 20

De esta manera, el valor de <em>x</em> es igual a 20 o x = 20.

Lo anterior lo podemos comprobar considerando las ecuaciones [1], [2] y [3]. Así tenemos que:

\\ \alpha = 2x + 10 [1]

Sustituimos x por el valor de 20:

\\ \alpha = 2*20 + 10 = 40 + 10 = 50

\\ \beta = x + 20 [2]

Hacemos lo mismo para [2]:

\\ \beta = 20 + 20

\\ \beta = 40

De esta manera:

\\ \alpha + \beta = 90 [3]

\\ 50 + 40 = 90

4 0
3 years ago
A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at
Soloha48 [4]

The equation you can use to solve the problem is;

50/30 = 300/x

Next Cross Multiply

50x = 9000

x = 9000/50

x = 180

The building's shadow is 180 feet tall

7 0
3 years ago
<img src="https://tex.z-dn.net/?f=-8%5E%5Cfrac%7B1%7D%7B3%7D" id="TexFormula1" title="-8^\frac{1}{3}" alt="-8^\frac{1}{3}" align
Charra [1.4K]

9514 1404 393

Answer:

  -2

Step-by-step explanation:

  -8^(1/3) = -(2^3)^(1/3) = -(2^(3/3)) = -2

6 0
3 years ago
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