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leva [86]
3 years ago
5

Find the area of a parallelogram bounded by the y-axis, the line x = 3, the line f (x) = 1 + 2x, and the line parallel to f (x)

passing through (2, 7
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0
There is not enough info ( ͡° ͜ʖ ͡°)
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3y-6 divided by 9 = 4-2 divided by -3
sweet [91]

Answer:

y = 16/9

Step-by-step explanation:

Assuming "y" is a variable

3y - 6/9 = 4 - 2/-3

3y - 2/3 =14/3

3y - 16/3 = 0

1/3 (9y - 2) = 14/3

ANSWER = y : 16/9

4 0
2 years ago
Read 2 more answers
Consider the following expression.<br> 5(1+6) (2b+7)<br> Select all of the true statements below.
Vesna [10]

<u>Answer:</u>

  • Option B
  • Option C
  • Option E

<u>Explanation:</u>

  • <em>Option B is true because both of the terms are constants. Hence, they are like terms.</em>
  • <em>Option C is true because the coefficient of a term is basically the constant. If there is no constant, then the coefficient is 1.</em>
  • <em>Option E is true because the expression has been multiplied by 5. </em>
6 0
2 years ago
James wants to buy some CDs that cost $14 each and a DVD that costs $23. He has $65. Write an equation (in the Show your work ar
notsponge [240]

Answer:

3

Step-by-step explanation:

65-23= 42

42/14= 3

4 0
3 years ago
Read 2 more answers
Which expression is equivalent to 3⁴ . 3-⁹
grigory [225]

Answer:

3^-5 or 1/3^5(b)

Step-by-step explanation:

3⁴•3^-9

When bases are same powers are to be added

So the above expression becomes

3^4+(-9)

3^4-9

3^-5

5 0
3 years ago
Read 2 more answers
a cardboard box holds 31.25 cubic inches of creamy butter. The butter is molded into a square prism that is 5 inches long. How m
lesya [120]

Answer:

62.5 \:in^2

Step-by-step explanation:

Volume of the butter in the cardboard = 31.25 cubic inches

Length of the Molded Square Prism =5 Inches

Let the length of the square cross sectional area = x

Volume of the Prism=x^2l

Since l=5 Inches

5x^2=31.25\\x^2=6.25\\x=2.5\: Inches

Next, we determine the surface area of the New Cardboard box to be made.

Length of the Cardboard Box=5 Inches

Length of the square cross sectional area = 2.5 Inches

Total Surface Area=2(x^2+xl+xl)=2(x^2+2xl)

=2(2.5^2+2(2.5)(5))\\=2(6.25+25)\\=2*31.25\\=62.5 \:in^2

Therefore, 62.5 \:in^2 of cardboard is needed,

4 0
3 years ago
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