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2 years ago

What is the property of an angle?

Mathematics

2 answers:

denis23 [38]2 years ago

4 0

Answer:

90 degrees = right angle. 180 or more = straight angle. 90 degrees or more = obtuse

Step-by-step explanation:

Elena-2011 [213]2 years ago

3 0

Answer:

When to lines intersect they create four angles. Each angle is opposite to another and form a pair of what are called opposite angles. Angles a and c are opposite angles. Angles b and d are opposite angles. Opposite angles are equal.

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Sonja [21]

Step-by-step explanation:

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2 years ago

Find the probability that he makes one of the two free throws using the multiplicativ

sertanlavr [38]

The probability is 1/2

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3 years ago

Amy, Rick, and Nisha are investing in three different types of stocks. What type of stock is each person Investing in?

GenaCL600 [577]

Answer: Amy = domestic stock

Rick = Employer stock

Nisha = International stock

Step-by-step explanation:

Amy invests in shares that won't be affected by exchange rate fluctuations. This shows that the stock that Amy invested in is a domestic stock. These are the stocks that are usually sold by companies in the home country.

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4 0

2 years ago

PLEASE ANSWER PART 2

labwork [276]

Answer:

it is 360

Step-by-step explanation:

all you do is subtact the first number by the second number

7 0

3 years ago

P(x)= 3x^3-5x^2-14x-4

nexus9112 [7]

$\displaystyle\\
P(x)=3x^3-5x^2-14x-4\\\\
D_{-4}=\{-4;~-2;~\underline{\bf -1};~1;~2;~4\}\\\\
\text{We observe that } \frac{-1}{3} \text{ is a solution of the equation:}\\
3x^3-5x^2-14x-4=0\\\\
$

$\displaystyle\\
\text{Verification}\\\\
3x^3-5x^2-14x-4=\\\\
=3\times\Big(-\frac{1}{3}\Big)^3-5\times\Big(-\frac{1}{3}\Big)^2-14\times\Big(-\frac{1}{3}\Big)-4=\\\\
=-\frac{1}{9}-\frac{5}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{14}{3}-4=\\\\
=-\frac{6}{9}+\frac{42}{9}- \frac{4\times 9}{9}=\\\\
 =-\frac{6}{9}+\frac{42}{9}- \frac{36}{9}= \frac{42-6-36}{9}=\frac{42-42}{9}=\frac{0}{9}=0\\\\
\Longrightarrow~~~P(x)~\vdots~\Big(x+ \frac{1}{3}\Big)\\\\
\Longrightarrow~~~P(x)~\vdots~(3x+1)$

$\displaystyle\\
3x^3-5x^2-14x-4=0\\
~~~~~-5x^2 = x^2 - 6x^2\\
~~~~~-14x =-2x-12x \\
3x^3+x^2 - 6x^2-2x-12x-4=0\\
x^2(3x+1)-2x(3x+1) -4(3x+1)=0\\
(3x+1)(x^2-2x -4)=0\\\\
\text{Solve: } x^2-2x -4=0\\\\
x_{12}= \frac{-b\pm \sqrt{b^2-4ac}}{2a}=\\\\=\frac{2\pm \sqrt{4+16}}{2}=\frac{2\pm \sqrt{20}}{2}=\frac{2\pm 2\sqrt{5}}{2}=1\pm\sqrt{5}\\\\
x_1 =1+\sqrt{5}\\
x_2 =1-\sqrt{5}\\
\Longrightarrow P(x)= 3x^3-5x^2-14x-4 =\boxed{(3x+1)(x-1-\sqrt{5})(x-1+\sqrt{5})}$

7 0

2 years ago

What is the property of an angle?​

What is the property of an angle?