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3 years ago

Find the value of x

Mathematics

1 answer:

antoniya [11.8K]3 years ago

3 0

Answer:

C. X = 10

Step-by-step explanation:

2x - 17 + (-8) + 2x = 15

4x + (-25) = 15

4x = 40

x = 10

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Christopher Columbus

Step-by-step explanation:

According to the hystoriartors:

Christopher Columbus

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2 years ago

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Someone answer this question I know your reading this.

IgorC [24]

Answer: A.

Step-by-step explanation:

To answer this, you must first understand what fractional exponents mean.

An exponent of 1 is simply the base itself. 7^1 = 7.

An exponent of 2 is squaring the base: 7^2 = 49.

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Therefore, an exponent of 1/3 is taking the cube root of the base.

In this case, the base is 2.03 * t.

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2 years ago

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viktelen [127]

4) The first and second terms for both ratios need to be in the same order.

Step-by-step explanation:

Given ratio is:

16:36

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The equivalent ratio that is given: 72:32

If we multiply the given ratio by 2: We get 32:72

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2 years ago

julsineya [31]

Answer: 41 vans will be needed.

Step-by-step explanation:

There are a total of 492 campers. We know that each van can hold a total of 12 passengers.

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2 years ago

Which is the simplified form of the expression ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript nega

AlekseyPX

Answer:

The option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Step-by-step explanation:

Given expression is ((2 Superscript negative 2 Baseline) (3 Superscript 4 Baseline)) Superscript negative 3 Baseline times ((2 Superscript negative 3 Baseline) (3 squared)) squared

The given expression can be written as

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

To find the simplified form of the given expression :

$[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2$

$=(2^{-2})^{-3}(3^4)^{-3}\times (2^{-3})^2(3^2)^2$ ( using the property $(ab)^m=a^m.b^m$ )

$=(2^6)(3^{-12})\times (2^{-6})(3^4)$ ( using the property $(a^m)^n=a^{mn}$

$=(2^6)(2^{-6})(3^{-12})(3^4)$ ( combining the like powers )

$=2^{6-6}3^{-12+4}$ ( using the property $a^m.a^n=a^{m+n}$ )

$=2^03^{-8}$

$=\frac{1}{3^8}$ ( using the property $a^{-m}=\frac{1}{a^m}$ )

Therefore $[(2^{-2})(3^4)]^{-3}\times [(2^{-3})(3^2)]^2=\frac{1}{3^8}$

Therefore option "StartFraction 1 Over 3 Superscript 8" is correct

That is $\frac{1}{3^8}$ is correct answer

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3 years ago

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