A would equal negative 60
Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
If we're trying to find the hypotenuse we'll take the
Getting 35.
35
Answer:
2×3=6
or 6×5=30
Step-by-step explanation:
Theres a lot!
Answer:
-5
-11x+2
Step-by-step explanation:
-4
-6x-1--5x+3=-5-11x+2
