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eduard
2 years ago
7

Solve for this equation z^2-12z=-13

Mathematics
1 answer:
ASHA 777 [7]2 years ago
5 0

Answer:

z=\sqrt{-1}

Step-by-step explanation:

z^2-12z=-13\\z^2-\frac{-12}{+12} =-13+12\\z^2=-1\\\sqrt{z^{2} } =\sqrt{-1}\\ z=\sqrt{-1}

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What is 0.3636363636 to the nearest thousandth?
Bad White [126]

Answer: 0.364

The reason that it would be 0.364 is because the thousandths place is the third decimal place, which would leave you with a 3 but since there is a 6 after the 3, the 3 would be rounded up to a 4.

6 0
2 years ago
Points F and E on the coordinate grid below show the positions of two midfield players of a soccer team:
Lelechka [254]

Answer:

F is E reflected across the y-axis; only the signs of the x-coordinates of F and E are different.

Step-by-step explanation:

The question is incomplete. Here is the complete question.

" Points F and E on the coordinate grid below show the positions of two midfield players of a soccer team:

Coordinate grid shown from negative 4 to positive 4 on x-axis and negative 4 to positive 4 on y-axis. From the origin, point E is 1.5 units to the left and 3 units up. From the origin, point F is 1.5 units to the right and 3 units up.

Which statement best describes the relationship between the positions of the two midfield players? (1 point)

Based on the coordinate of E;

The value on the x axis is -1.5 since the point is 1.5unitsTO THE LEFT from the origin(-ve x-axis acts towards the left in space). The value on the y-axis will be +3units since its 3units UP(+ve y axis acts upward).

The E coordinates will therefore be (-1.5, 3)

Similarly, for coordinate F:

If from the origin, point F is 1.5 units TO THE RIGHT, then the x-axis will be +1.5 (x-axis is positive towards the right) and +3 units up(+ve y axis acts upward).

The F coordinate will therefore be;

(1.5, 3).

From both coordinates, it can be seen that both x axis are of the same value but different signs. This means that the points E and F will act in the opposite side of the y-axis and a reflector of each other.

Based on the explanation above, it can be concluded that "F is E reflected across the y-axis; only the signs of the x-coordinates of F and E are different."

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