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velikii [3]
3 years ago
12

If y varies directly as x, and y is 20 when x is 4, what is the constant of variation for this relation?

Mathematics
2 answers:
bulgar [2K]3 years ago
5 0

Answer:

The answer is 5

Step-by-step explanation:

on edge 2021

arlik [135]3 years ago
4 0

Answer:

5

Step-by-step explanation:

20/5 = 5/1

so the answer is c

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6 0
3 years ago
MAT 171
steposvetlana [31]

Using the Factor Theorem, the polynomials are given as follows:

1. P(x) = x^5 + 2x^4 - 7x^3 + x^2

2. P(x) = 0.8(x^4 - 4x^3 - 16x^2 + 64x)

3. P(x) = -0.1(x³ - 4x² - 3x + 18)

<h3>What is the Factor Theorem?</h3>

The Factor Theorem states that a polynomial function with roots x_1, x_2, \codts, x_n is given by:

f(x) = a(x - x_1)(x - x_2) \cdots (x - x_n)

In which a is the leading coefficient.

Item a:

The parameters are:

a = 1, x_1 = x_2 = 1, x_3 = x_4 = 0, x_5 = -4

Hence the equation is:

P(x) = (x - 1)²x²(x + 4)

P(x) = (x² - 2x + 1)(x + 4)x²

P(x) = (x³ + 2x² - 7x + 1)x²

P(x) = x^5 + 2x^4 - 7x^3 + x^2

Item b:

The roots are:

x_1 = x_2 = 4, x_3 = 0, x_4 = -4

Hence:

P(x) = a(x - 4)²x(x + 4)

P(x) = a(x² - 16)x(x - 4)

P(x) = a(x³ - 16x)(x - 4)

P(x) = a(x^4 - 4x^3 - 16x^2 + 64x)

It passes through the point x = 5, P(x) = 36, hence:

45a = 36.

a = 4/5

a = 0.8

Hence:

P(x) = 0.8(x^4 - 4x^3 - 16x^2 + 64x)

Item 3:

The roots are:

x_1 = x_2 = 3, x_3 = -2

Hence:

P(x) = a(x - 3)²(x + 2)

P(x) = a(x² - 6x + 9)(x + 2)

P(x) = a(x³ - 4x² - 3x + 18)

For the y-intercept, x = 0, y = -1.8, hence:

18a = -1.8 -> a = -0.1

Thus the function is:

P(x) = -0.1(x³ - 4x² - 3x + 18)

More can be learned about the Factor Theorem at brainly.com/question/24380382

#SPJ1

5 0
2 years ago
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