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2 years ago

Please show the work. 5256÷52, 5624÷46, 756÷36, 2760÷12. It's a lot to do, so I'm making this 40 points.

1 answer:

6 0

101 r4,122 r12,21,230 hope this helps these are the answers in order I don’t really have any paper to do the math on rn but I’m pretty sure these are the answers!

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Even more trig ratios see attachment

egoroff_w [7]

Step-by-step explanation:

1. Use the Pythagorean theorem to solve for side KM:

16^2+KM^2=34^2
256+KM^2=1156
KM^2=900
KM=30

2. Cosine is adjacent over hypotenuse, so cosine of M would be KM/34, or 30/34

3. Tangent is opposite over adjacent, so tangent of L will be KM/16, or 30/16

4. Sine is opposite over hypotenuse, so sine of M will be 16/34

5. KM=30, solved for in step 1.

hope this helps!!

4 0

2 years ago

Draw a conclusion is the statement below always sometimes or never true give at least two examples to support your reasoning the

hodyreva [135]

It's sometimes true.

One example is the least common multiple of 2 and 3 is 6, which is their product.

But the product isn't always the answer because (example 2:) the least common multiple of 6 and 10 is 30 because 6*5=30 and 3*10=30, however 6*10 is 60.

Ergo, it is only sometimes true.

3 0

2 years ago

Taylor ran 2 1/4 miles and walked 2 4/5 miles. How far did she run and walk

irinina [24]

Okay. So, we should convert fractions to the least common denominator, which is 20. That would be 2 5/20 and 2 16/20. Add both of those numbers up to get 5 1/20. Taylor ran and walked 5 1/20 miles.

5 0

2 years ago

Is 0.1304347826 a rational number?

VLD [36.1K]

Yes it is a rational number

4 0

2 years ago

Two corresponding sides of similar triangles are 2 cm and 5 cm. What is the area of the second triangle if the area of the first

Stella [2.4K]

Answer:

(1) Area of second triangle= 50 cm^2.

(2) Area of ΔABC=98 cm^2.

and Area of ΔDFG=175 cm^2.

Step-by-step explanation:

<em>" For two similar triangles the ratio of sides is equal to the ratio of square of their areas".</em>

i.e. if a,b are the corresponding sides of two similar triangles and let A and B denote the area of two triangles then we have the relation as:

$\dfrac{a^2}{b^2}=\dfrac{A}{B}$

(1)

for the first question:

we have a=2, b=5.

A=8 cm^2.

Hence,

$\dfrac{2^2}{5^2}=\dfrac{8}{B}\\\\\dfrac{4}{25}=\dfrac{8}{B}$

B=50 cm^2.

Hence, the area of second triangle is 50 cm^2.

(2)

In second option we have:

a=6 and b=5.

A-B=77 cm^2.

A=77+B

$\dfrac{6^2}{5^2}=\dfrac{A}{B}\\ \\\dfrac{36}{25}=\dfrac{77+B}{B}\\ \\36B=25\times77+25B\\\\36B-25B=25\times77\\\\11B=25\times77\\\\B=25\times7\\\\B=175$

Hence area of second triangle i.e. ΔDFG is 175 cm^2.

and area of first triangle i.e. ΔABC=175-77=98 cm^2.

8 0

2 years ago