Determine which triangle appers to be acute?

Mathematics

1 answer:

Elena-2011 [213]3 years ago

7 0

Which triangles am I supposed to choose from?

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simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed

Gnoma [55]

Answer:

$\frac{x^{2} + 19x - 56}{4 {x}^{2} - 32x}$

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

$\frac{x + 7}{4x} + \frac{5}{x - 8}$

$= \frac{(x + 7)(x - 8)}{4x(x - 8)} + \frac{5(4x)}{4x(x - 8)}$

$= \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}$

$= \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4x(x - 8)}$

$= \frac{ {x}^{2} + 19x - 56}{4 {x}^{2} - 32x}$

7 0

2 years ago

Is this correct help plzz

const2013 [10]

None of the offered choices is correct.

The radical cannot be simplified. If rewritten, it must be written as something like
$x \sqrt[3]{ \frac{6}{x}}$
or
$\frac{6x}{ \sqrt[3]{36x}}$