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1 year ago

The slope of the line that passes through the points (-10,y) and (5, 2) is 2/5. What is the value of y?

Mathematics

1 answer:

Murrr4er [49]1 year ago

7 0

Answer:

C, -4

Step-by-step explanation:

slope=change in y/change in x

$\frac{2 - y}{5 - ( - 10)} = \frac{2}{5}$

$\frac{2 - y}{5 + 10} = \frac{2}{5}$

multiply both sides by 2/5

$2 - y = \frac{2}{5} (5 + 10)$

simplify the right side. 2/5 × 5 = 2 and 2/5 × 10 = 4

$2 - y = 2 + 4$

$2 - y = 6$

bring y to the other side by adding y on both sides

$2 = 6 + y$

subtract 6 on both sides

$2 - 6 = y$

so y is -4

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A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

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2 years ago

What is 4r+9r-11r+7r please im not trying to fail

kaheart [24]

Answer:

Step-by-step explanation:

combine like terms in PEMDAS order. Add 4, 9, and 7, then, subtract 11.

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2 years ago

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If the two terms of a gemotric sequence are a1=216, and a2=72, which is the third term? a3?

Ierofanga [76]

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