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3 years ago

Question number 1 pls

Mathematics

2 answers:

loris [4]3 years ago

8 0

X is time spent walking the dog, y is the time washing cars

$x + y \leqslant 20 \\ 7.5x + 6y \geqslant 92$

Sedaia [141]3 years ago

5 0

Let x=dog-walking job

Let y= car was attendant

Inequality: 7.50x+6y>92

Inequality: x+y<20

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Last month 288 people attended the monthly bingo night. This month 243 people attended bingo night. To the nearest tenth of a pe

adelina 88 [10]

Answer:

15.625

Step-by-step explanation:

old number = 288

new number = 243

percent decrease = (old - new / new ) * 100

= (288 - 243 / 288) * 100

= 45 / 288 * 100

= 15.625

7 0

3 years ago

Determine the intercept of the line.

timama [110]

I believe it is

X= (-7.5,0)
Y= (5.5,0)

7 0

3 years ago

The values for three different sets of data are shown below.

Amiraneli [1.4K]

Answer:

I would say C Sets 2 and 3 contain outliers.

Step-by-step explanation:

Set 2 has an outlier of 90, and set 3 contains an outlier of 40. 40 is not as much of an outlier as 90, so I'm not absolutely sure.

6 0

4 years ago

Read 2 more answers

Suppose you want to eat lunch at a popular restaurant. The restaurant does not take reservations, so there is usually a waiting

grin007 [14]

Answer:

a) $z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{15-19}{4} =-1$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-1)=1-P(z$

And replacing we got:

$P(X >20| X>15)= \frac{0.401}{0.841}= 0.477$

b) $z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{18-19}{4} =-0.25$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-0.25)=1-P(z$

And replacing we got:

$P(X >20| X>18)= \frac{0.401}{0.599}= 0.669$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the length of time waiting to be seated of a population, and for this case we know the distribution for X is given by:

$X \sim N(19,4.0)$

Where $\mu=19$ and $\sigma=4.0$

Part a

For this cae we want to find this probability:

$P(X >20| X>15)$

And if we use the conditional probability formula we got:

$P(X >20| X>15)= \frac{P(X >20 \cap X>15)}{P(X>15)}=\frac{P(X>20)}{P(X>15)}$

We can solve the problem using the z score formula given by:

$z = \frac{x-\mu}{\sigma}$

$z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{15-19}{4} =-1$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-1)=1-P(z$

And replacing we got:

$P(X >20| X>15)= \frac{0.401}{0.841}= 0.477$

Part b

$P(X >20| X>18)= \frac{P(X >20 \cap X>18)}{P(X>18)}=\frac{P(X>20)}{P(X>18)}$

We can solve the problem using the z score formula given by:

$z = \frac{x-\mu}{\sigma}$

$z_1 =\frac{20-19}{4} =0.25$

$z_2 =\frac{18-19}{4} =-0.25$

And we can use the complement rule and we got:

$P(z>0.25)=1-P(z$

$P(z>-0.25)=1-P(z$

And replacing we got:

$P(X >20| X>18)= \frac{0.401}{0.599}= 0.669$

5 0

4 years ago

Can you guys please help I'll give brainliest

shepuryov [24]

Assuming the 10 represents the circumference of the circle (not really clear in the pic) then the area of the circle is found by this equation:

Area=c^2/4pi
(C being circumference, the ^2 meaning squared, and pi of course being the infinite number found by Archimedes, but normally calculated as 3.14 or 3.14)

Using that equation (substitute the C for the 10) you get 7.9577

Round this off to about 7.96, or 8. Your choice.
~Hope this helps!

8 0

3 years ago

Read 2 more answers