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3 years ago

What is the exponential form for 7^√x^3

Mathematics

2 answers:

Semenov [28]3 years ago

7 0

Answer:

The exponential form of this would be (7x)^3/2

Step-by-step explanation:

The square root symbol is the same as writing raised to the 1/2. So we can rewrite the equation as:

[(7x)^1/2]^3

Then we can multiply the two exponents in this case giving us

(7x)^3/2

Elodia [21]3 years ago

5 0

(√7)3=732

Explanation:

To write

(√7)3

in exponential form, one needs two identities - n√a=a1n

and (am)n=a(m×n)

which is true for all rational

m and n.

Hence,

(√7)3= (712)3

= 7(12×3)

= 732

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The top of the tallest mast of a sail boat is 44 feet above sea level. The boat's anchor is resting on the sea bed 38 feet below

g100num [7]

Positive 6 hope this helps

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3 years ago

Which real world situation cannot be represented by X +8 equals X 2+4

AlekseyPX

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3 years ago

Someone answer please I would be very grateful

Reil [10]

Answer:

Part A : 9.555 . 10^38

Part B : 7.4 . 10^-3

Step-by-step explanation:

$3.9 \: . \: {10}^{33} . \: 2.45 \: . \: {10}^{5} \\ 3.9 \: . \: 2.45 \: . \: {10}^{33 + 5} \\ 9.555 \: . \: {10}^{38} \\$

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A blood cell is too small. So the more reasonable measurement is 0.0074mm.

7 0

3 years ago

Write the point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of 1/4 include all

amid [387]

<u>Answer:</u>

The point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of $\frac{1}{4}$ is 4x + y -25 = 0

<u>Solution:</u>

The point slope form of the line that passes through the points $\left(x_{1} y_{1}\right)$ and perpendicular to the line with a slope of “m” is given as

$\bold{y-y_{1}=-\frac{1}{m}\left(x-x_{1}\right)}$ ---- eqn 1

Where “m” is the slope of the line. $x_{1} \text { and } y_{1}$ are the points that passes through the line.

From question, given that slope “m” = $\frac{1}{4}$

Given that the line passes through the points (5,5).Hence we get

$x_{1}=5 ; y_{1}=5$

By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope $\frac{1}{4}$ can be found out.

y - 5 = -4(x - 5)

y - 5 = -4x + 20

on simplifying the above equation, we get

y - 5 + 4x -20 = 0

4x + y - 25 = 0

hence the point slope form of given line is 4x + y - 25 = 0

3 0

3 years ago

A marble started with 0.0018 J of Potential Energy and at some point later it has only 0.0011 J of Potential Energy. How much Ki

Yakvenalex [24]

Answer:

the Kinetic Energy of the marble at the later point is 0.0007 J

Step-by-step explanation:

Given;

initial potential energy of the marble, P.E₁ = 0.0018 J

final potential energy of the marble, P.E₂ = 0.0011 J

At the initial starting point, the total mechanical energy is;

M.E = K.E + P.E

at the initial starting point, velocity = 0

M.E = 0 + P.E

M.E = P.E = 0.0018 J

At some point later, the total mechanical energy is;

M.E = P.E + K.E

0.0018 J = 0.0011 J + K.E

0.0018 J - 0.0011 J = K.E

0.0007 J = K.E

Therefore, the Kinetic Energy of the marble at the later point is 0.0007 J

8 0

3 years ago