Answer:
Explanation:
<u>The Differential of Multivariable Functions</u>
Given a multivariable function V(r,h), the total differential of V is computed by
The volume of a cylinder of radius r and height h is
Let's compute the partial derivatives
The total differential is
The differential dr is approximated to and the differential dh is approximated to . We can see the increment of radius is the thick of the metal in the sides, and the increment of the height is the thick of the metal in the top and bottom. Thus dr=0.05 cm, dr=0.2 cm
Then I walked into Mr. and Mrs. Frank's bedroom. On the floor, amidst the chaos of papers and books, my eye lit on the little red-orange checkered, cloth-bound diary that Anne had received from her father on her thirteenth birthday. She loves Anne and respects her work.
I hope this helps you.
Answer:
#include <stdio.h>
int main()
{
int threshold = 5;
int i,j;
int matrix[5][5] = {{4, 4, 4, 2, 2},
{4, 2, 2, 2, 2},
{2, 2, 8, 7, 2},
{2, 8, 8, 8, 2},
{8, 2, 2, 2, 8}};
int row=(sizeof(matrix)/sizeof(matrix[0])); // length of row
int column=(sizeof(matrix)/sizeof(matrix[0][0]))/row; // length of column
printf("Input matrix value:\n");
for(i=0; i <5; i++)
{
for(j=0; j<5; j++)
{
printf("%d ", matrix[i][j]);
}
printf("\n");
}
printf("\n");
for(i=0; i<column; i++)
{
for(j=0; j<column; j++)
{
if ( (j == 0) || (j == column-1) ) // print 0 for first and last element of every row
printf("%d ", 0);
else
{
if(matrix[i][j] > threshold) // veify whether the element is more than threshold
{
printf("%d ",1);
}
else
{
printf("%d ", 0);
}
}
}
printf("\n");
}
return 0;
}
Answer:
$958.25
Explanation:
PV = FV(1 +r)^(-t) . . . . present value of an amount earning rate r compounded annually for t years
PV = $3000(1.08^-5) ≈ $2041.75
The equivalent present value is $2041.75.
__
This amount is less than the offered amount by ...
$3000 -2041.75 = $958.25
She should pay you $958.25 less in order to make the offers equivalent.