Answer:
much faster than average
Explanation:
did it on edge (2022-2032)
Answer:
START
READ ID_Number
READ Item_description
READ length_of_auction_Days
READ minimum_required_bid
IF minimum_required_bid GREATER THAN 100
THEN
DISPLAY
Item Details are
Item Id : ID_Number
Item Description: Item_description
Length Action days: length_of_auction_Days
Minimum Required Bid: minimum_required_bid
END
Explanation:
Answer:
the critical flaw length is 10.06 mm
Explanation:
Given the data in the question;
plane strain fracture toughness = 92 Mpa√m
yield strength σ = 900 Mpa
design stress is one-half of the yield strength ( 900 Mpa / 2 ) 450 Mpa
Y = 1.15
we know that;
Critical crack length = 1/π( / Yσ )²
we substitute
= 1/π( 92 Mpa√m / (1.15 × 450 Mpa )²
= 1/π( 92 Mpa√m / (517.5 Mpa )²
= 1/π( 0.177777 )²
= 1/π( 0.03160466 )
= 0.01006 m = 10.06 mm
Therefore, the critical flaw length is 10.06 mm
{ = ( 10.06 mm ) > 3 mm
The critical flow is subject to detection