Should be a Polar-Covalent bond.
Explanation:
Newton's second law simply says that the net force on an object is equal to the object's mass times its acceleration.
∑F = ma
For example, think of a game of tug-of-war, in which two teams pull on a rope in opposite directions.
If the forces are equal (balanced), then the net force is 0 N, so Newton's second law tells us that the rope's acceleration is 0 m/s².
If the forces are not equal (unbalanced), then the net force is not 0 N, and the rope will accelerate in the direction of the net force.
If you meant solve, the answer would be v= A times t
You see, to get rid of an variable on one side, you must do the opposite of what is being done to it, in this case, multiply because division. After this, we must do what we did to one side to the other side. This creates the equation above!
Answer:
X = 5.44 m
Explanation:
First we can calculate the normal force acting from the floor to the ladder.
W₁+W₂ = N
W1 is the weigh of the ladder
W2 is the weigh of the person
So we have:
The friction force is:
Now let's define the conservation of torque about the foot of the ladder:
Solving this equation for X, we have:
Finally, X = 5.44 m
Hope it helps!
<h3>Answer: 2 seconds</h3>
This problem is equivalent to kicking the ball 8 m/s and it rolls to a point 16 meters away, and everything is on a flat ground (with no cliff). This is because the horizontal component of the velocity does not get affected by how tall the cliff is and the force of gravity. Note how the height of the cliff isn't even mentioned. So that's a clue that we can ignore it.
If x is the number of seconds, then 8x is the distance in meters it travels. So we have 8x = 16 solve to x = 2. The ball travels for 2 seconds before reaching its target.
