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arlik [135]
3 years ago
10

Calculate the energy of 1kg of concrete from 20⁰c to 30⁰c​

Physics
1 answer:
mixas84 [53]3 years ago
3 0

Answer:

9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.

Explanation:

In this exercise we need to determined the sensible heat store in a kilogram of concrete due to a change in temperature. Sensible heat (Q), measured in kilojoules, is defined by the following expression:

Q = m\cdot c\cdot (T_{f}-T_{o}) (1)

Where:

m - Mass, measured in kilograms.

c - Average specific heat of concrete, measured in kilojoules per kilogram-degree Celsius.

T_{o}, T_{f} - Initial and final temperatures of concrete, measured in degrees Celsius.

If we know that m = 1\,kg, c = 0.9\,\frac{kJ}{kg\cdot ^{\circ}C}, T_{o} = 20\,^{\circ}C and T_{f} = 30\,^{\circ}C, then the energy store in a kilogram of concrete is:

Q = (1\,kg)\cdot \left(0.9\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (30\,^{\circ}C-20\,^{\circ}C)

Q = 9\,kJ

9 kilojoules of energy are stored in a kilogram of concrete due to sensible heat.

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