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3 years ago

__________________ are numerical data; facts and figures used to analyze problems.

Mathematics

2 answers:

son4ous [18]3 years ago

8 0

<h2>Answer:</h2>

Statistics are numerical data; facts and figures used to analyze

<h2>Step-by-step explanation:</h2>

<u>Statistics--</u>

Statistics is a branch of mathematics that deals with the collection, interpretation, organizing and analyzing of a large set of data in order to draw the inference for the whole populations which are included in a sample.

Hence, option: a is the correct answer.

a. Statistics.

amid [387]3 years ago

4 0

The answer is A. Statistics. Hope this helps!

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WILL GIVE BRAINLIEST!

lesya [120]

Answer:

425

Step-by-step explanation:

225/24 then multiply the answer by 40

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2 years ago

A silo is a composite of a cylindrical tower with a cone for a roof. Find the volume of the silo if the

xxMikexx [17]

Answer:

5127079.21 cubic feet

Step-by-step explanation:

The silo is in the shape of a cylinder and a cone.

The volume of the silo will be the sum of the volumes of the cylinder and the cone.

Therefore, its volume is:

$V = \pi r^2h + \frac{1}{3} \pi rH$

where r = radius of cylinder and cone

h = height of cylinder

H = height of cone

The radius of the base is 120 feet, the height of the roof (cone) is 25 feet. The height of the entire silo is 130 feet. This means that the height of the cylinder is:

130 - 25 = 105 feet

Therefore, the volume of the silo is:

$V = (\pi * 120^2 * 105) + (\frac{1}{3} * 120^2 * 25)\\\\V = 4750088.09 + 376991.12\\\\V = 5127079.21 ft^3$

The volume of the silo is 5127079.21 cubic feet.

3 0

2 years ago

Which of these limits evaluate to 0?

Vikentia [17]

<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

$\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\$

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Part II

$\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\$