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vodomira [7]
3 years ago
12

The second of the three numbers is 4 times the first the third is 2 more than the second. If the second number is decreased by t

wice the third the result is 28 what are the three numbers
Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

the three numbers = -8, -32, -30

Step-by-step explanation:

let the first number = a

let the second number = b

let the third number = c

From the first statement:  b = 4a

From the second statement: c = b + 2

From the third statement: b - 2c = 28

From the above equations, we can solve (1) and (2) together.

c = b + 2

b = c - 2

Also, b - 2c = 28

(c - 2) - 2c = 28

c - 2 - 2c = 28

-c = 30

c = -30

b = -30 - 2

  = -32

b = 4a

a = b/4

a = -32/4

a = -8

Therefore, the three numbers = -8, -32, -30

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-2x-2y=-8<br> -4x-8y=-20
Citrus2011 [14]

Answer:

-2x-2y=-8

-4x-8y=-20

From the 1st eqn

Dividing through by 2

you have

-x-y=-4

Multiply through by -(minus)

x+y=4

x=4-y

Substitute into eqn 2

-4x-8y=-20

-4(4-y)-8y=-20

-16 + 4y - 8y = -20

-4y = -20 +16

-4y = -4

y= 1

Substitute into any of the other eqn's to get x

x= 4-y

x= 4-1

x=3

8 0
3 years ago
I have a question about polynomial division it is in the picture
Cloud [144]

To answer this question, we have to do the long division process for polynomials. We can do the operation as follows:

To do this division process, we have:

1. Divide the first term of the dividend by the first element of the divisor. They are:

\frac{-4x^3}{4x^2}=-x

2. Now, we have to multiply this result by the divisor, and the result will change its sign since we have to subtract that result from the dividend as follows:

-x\cdot(4x^2_{}-4x-4)=-4x^3+4x^2+4x

And since we to subtract this result from the dividend, we end up with:

-(-4x^3+4x^2+4x)=4x^3-4x^2-4x

3. Then we have the following algebraic addition:

\frac{\begin{cases}-4x^3+24x^2-15x-15 \\ 4x^3-4x^2-4x\end{cases}}{20x^2-19x-15}

4. Again, we need to divide the first term of the dividend by the first term of the divisor as follows:

\frac{20x^2}{4x^2}=5

5. And we have to multiply 5 by the divisor, and the result will be subtracted from the dividend:

5\cdot(4x^2-4x-4)=20x^2-20x-20

Since we have to subtract this from the dividend, we have:

-(20x^2-20x-20)=-20x^2+20x+20

6. And we have to add this algebraically to the dividend we got in the previous step:

\frac{\begin{cases}20x^2-19x-15 \\ -20x^2+20x+20\end{cases}}{x+5}

And this is the remainder of the division, x + 5.

As we can see from the division process, we got as:

1. The quotient: -x + 5

q=-x+5

2. The remainder: x + 5.

R=x+5

Since we have that the dividend = divisor * quotient + remainder.

Therefore, the result for this division is:

-4x^3+24x^2-15x-15=(4x^2-4x-4)\cdot(-x+5)+(x+5)

4 0
1 year ago
Solve for each unknown variable, #67
mel-nik [20]
3x +10= 2x + 34

x = 24

82°
3 0
4 years ago
The diameter of a circle is 10 in. Find its area in terms of pi
elena55 [62]

Answer:

25 pi

Step-by-step explanation:

4 0
3 years ago
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HELP PLEASE ILL GIVE YOU BRAINLIST !! I DONT UNDERSTAND IT .
inn [45]

Step-by-step explanation:

35 + 35 = 70

180 - 70 = 110

180 - 110 = 70

70  + 70 = 140

180 - 140 = 40

so the answer is 40

7 0
3 years ago
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