Classify 3x^5-8x^3-2x^2+5 by number of terms. Please show steps?
1 answer:
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<h2>Answer with explanation:</h2>
Given : Sample size
Sample mean :
Sample standard deviation :
Let be the population mean of "like" ratings of male dates made by the female dates.
As per question ,
Null hypothesis :
Alternative hypothesis : , It means the test is a one-tailed t-test. ( we use t-test when population standard deviation is unknown.)
Test statistic:
For 0.05 significance and df =188 (df=n-1) p-value = .001582. [By t-table]
Since .001582< 0.05
Decision: p-value < significance level , that means there is statistical significance, so we reject the null hypothesis.
Conclusion : We support the claim at 5% significance that t the population mean of such ratings is less than 8.00.