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borishaifa [10]
3 years ago
7

Which quadratic function best fits this data?

Mathematics
1 answer:
Vika [28.1K]3 years ago
3 0

The data has a peak at x=5, so we expect it to be modeled with a parabola that opens downward. That is the x² coefficient will be negative.

For x=1, the third choice gives a better approximation to (x, y) = (1, 32) than does the first choice. It is appropriate to choose

... y = -11.41x²+154.42x-143.9

_____

The quadratic regression function of a graphing calculator confirms this choice.

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What are the 6 steps to designing a statistical study
Fittoniya [83]

Answer:

Step 1: Write your hypotheses and plan your research design

Step 2: Collect data from a sample

Step 3: Summarize your data with descriptive statistics

Step 4: Test hypotheses or make estimates with inferential statistics

Step 5: Interpret your results

Step-by-step explanation:

7 0
1 year ago
If a polynomial doesn’t factor, it’s called _______.
ivanzaharov [21]
It would be called prime.
8 0
3 years ago
Bbbbbbbbbbbbbbbbbbbbb
mel-nik [20]

Answer:

BBAB

Step-by-step explanation:

DU DU DU DU DU DU DU DU DU

7 0
3 years ago
Daniya can complete a job in 6 minutes, while it takes Abraham 9 minutes to
lora16 [44]

Answer:

(eduacted guess) 7 minutes, 30 seconds

Step-by-step explanation:

May not be correct but what I did was find the average of 6 and 9. You add the 6 and the 9 (15), then divide it by 2.

3 0
3 years ago
I know the answer just need someone explain to me how to solve it
Vinvika [58]

The logarithm of a quotient can be written as a difference of logarithms:

\log_3\left(\dfrac uv\right) = \log_3(u) - \log_3(v)

You can also think of this as a combination of the product-to-sum and reciprocal/power properties of logarithms:

\log_3\left(\dfrac uv\right) = \log_3\left(u \times \dfrac1v\right) = \log_3(u) + \log_3\left(\dfrac1v\right) = \log_3(u) - \log_3(v)

To summarize,

\log_b(mn) = \log_b(m)+\log_b(n)

\log_b\left(\dfrac mn\right) = \log_b(m) - \log_b(n)

\log_b\left(m^n\right) = n \log_b(m)

3 0
2 years ago
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