Answer:
The value of the appropriate z test statistic to test this claim is 0.48.
Step-by-step explanation:
We are given that a potential competitor has been conducting blind taste tests on its blend and finds that 48% of consumers strongly prefer its French Roast to yours.
After tweaking its recipe, the competitor conducts a test with 144 tasters, of which 72 prefer its blend.
<u><em /></u>
<u><em>Let p = proportion of consumers who prefers new blend.</em></u>
So, Null Hypothesis, : p 48% {means that the new blend is preferred by less than or equal to 48% of consumers}
Alternate Hypothesis, : p > 48% {means that the new blend is preferred by more than 48% of consumers}
The test statistics that would be used here <u>One-sample z proportion</u> <u>statistics</u>;
T.S. = ~ N(0,1)
where, = sample proportion of tasters prefer new blend = = 0.50
n = sample of tasters = 144
So, <u><em>test statistics</em></u> =
= 0.48
Hence, the value of the appropriate z test statistic to test this claim is 0.48.