Explanation: find the hypotenuse of the 1st triangle a^2 + b^2 = c^2 -> 9*9 + 5*5 = c^2 Which is 81+25 = c^2 -> 106 = c^2 now square root c = 10.3
Now you have the hypotenuse of the triangle on the left notice that the hypotenuse we just solved for is actually a leg for the triangle on the right. Now you can use the hypotenuse formula for x.
10.3^2 + 4^2 = x^2 -> 106.09 + 16 = x^2 Next, 122.09 = x^2 now we need to square root to isolate the square (2). x = 11.04 when rounded the closest radical is you answer x=11
