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2 years ago

7

This trapezoid based right pyramid has a volume of 48m cubed with a height of 8 and slant height of 14 what is the area of the b

ase of the pyramid

1 answer:

laila [671]2 years ago

6 0

Answer:

18

Step-by-step explanation:

Khan Academy

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The perimeters of the square and the regular pentagon are equal.

Mashutka [201]

Answer:

the answer is 60 not 42 goodluck

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2 years ago

Read 2 more answers

What is the following product? 3sqrt4 times sqrt3

Harman [31]

Answer:

$\sqrt[6]{432}$

Step-by-step explanation:

$\sqrt[3]{4}\cdot\sqrt{3}=4^{\frac{1}{3}}\cdot3^\frac{1}{2}=(2^2)^\frac{1}{3}\cdot3^\frac{1}{2}=(2^\frac{4}{3})^\frac{1}{2}\cdot3^\frac{1}{2}=(2^\frac{4}{3}\cdot3)^\frac{1}{2}=(2^4\cdot27)^\frac{1}{6}=432^\frac{1}{6}=\sqrt[6]{432}$

3 0

2 years ago

How do u write 25,678 in number name

egoroff_w [7]

Answer:

twenty-five thousand, six hundred seventy-eight

Step-by-step explanation:

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3 years ago

What if X if [ -1 -2 4 8] +X= [-5 -1 2 1]?

Arada [10]

Answer:

[-4 1 -2 - 7]

Step-by-step explanation:

[-1 - 2 4 8] + X = [-5 - 1 2 1]

X= [-5 - 1 2 1]- [-1 - 2 4 8]

X=[-5-(-1) - 1-(-2) 2-4 1-8]

X=[-4 1 - 2 - 7]

3 0

3 years ago

Martin throws a ball straight up in the air. the equation h(t) = -16t^2 + 40t + 5 gives the height of the ball, in feet, t secon

Lisa [10]

Answer:

2.62 seconds

Step-by-step explanation:

Let

t ----> the time in seconds

h(t) ----> he height of the ball, in feet

we have

$h(t)=-16t^2+40t+5$

we know that

When the ball hits the ground, the height is equal to zero

so

$-16t^2+40t+5=0$

The formula to solve a quadratic equation of the form

$at^{2} +bt+c=0$

is equal to

$t=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$-16t^2+40t+5=0$

so

$a=-16\\b=40\\c=5$

substitute in the formula

$t=\frac{-40\pm\sqrt{40^{2}-4(-16)(5)}} {2(-16)}$

$t=\frac{-40\pm\sqrt{1,920}} {-32}$

$t=\frac{-40+\sqrt{1,920}} {-32}=-0.12\ sec$

$t=\frac{-40-\sqrt{1,920}} {-32}=2.62\ sec$

therefore

The solution is t=2.62 seconds

4 0

2 years ago