Corresponding angles for parallel lines r and s cut by transversal q. Corresponding angles are congruent angles.
1 and 9
2 and 10
3 and 11
4 and 12
Corresponding angles for parallel lines p and q cut by transversal s. Corresponding angles are congruent angles.
11 and 15
9 and 13
12 and 16
10 and 14
Corresponding angles for parallel lines p and q cut by transversal r. Corresponding angles are congruent angles.
1 and 5
3 and 7
2 and 6
4 and 8
Linear pair theorem. These 2 angles are equal to 180°
∠1 + ∠2 = 180
∠3 + ∠4 = 180
∠9 + ∠10 = 180
∠11 + ∠12 = 180
∠5 + ∠6 = 180
∠7 + ∠8 = 180
∠13 + ∠14 = 180
∠15 + ∠16 = 180
∠1 + ∠3 = 180
∠2 + ∠4 = 180
∠9 + ∠11 =180
∠10 + ∠12 = 180
∠5 + ∠7 = 180
∠6 + ∠8 = 180
∠13 + ∠15 = 180
∠14 + ∠16 = 180
Vertical angles theorem. Vertical angles are congruent.
1 and 4
2 and 3
9 and 12
10 and 11
5 and 8
6 and 7
13 and 16
14 and 15
1 and 3 they share a relationship of +2, 3 and 6 share x2, 5 and 8 share +3, 7 and 21 share x3
7 and 14 can be divided in to two
Answer:
the answer is c
Step-by-step explanation:
the answer is C because m A equals that is you know how too do it
Answer:
Kindly check explanation
Step-by-step explanation:
Given the following :
40 metres covered in 6 seconds
Max speed attained after 6seconds
75 meters covered after 11 seconds
Average Speed for first 40 meters :
Speed = distance / time
Speed = 40m / 6s
Speed = 6.67m/s
To obtain the maximum speed :
Next (75 - 40) meters = 35 meters was covered in (11 - 6)seconds = 5 seconds
Speed at this point is maximum :
Hence, maximum speed = (35m / 5s) = 7m/s
Suppose, Manuel runs for an additional z seconds after reaching max speed :
Distance from starting line 6+z seconds after race started?
Distance after 6 seconds = 40 metres
Distance after z seconds = 7 * z
Total distance = (40 + 7z)
What is Manuel's distance from the starting line x seconds after the race started (provided x≥6x)?
Distance for first 6 seconds = 40 meters + distance covered after 6 seconds = (7 * (x-6))
40 + 7(x - 6)
