The vertex of the parabola is at (5,3) and its focal length is 8/4 = 2.
Since it opens to the right, the directrix will be a vertical line 2 units to the left of the vertex, so its equation will be x=(5-2), or x=3
Answer:
$ 50
Step-by-step explanation:
sp = mp - discount percent of mp
or, 42 = mp - 16/100 * mp
or, 42 = 84 mp / 100
so, mp = 50
Step-by-step explanation:

Answer:
The perimeter is 66.9 units
Step-by-step explanation:
See the attached figure with letters to better understand the problem
step 1
In the right triangle ABD
<em>Find the length side AD</em>
----> by TOA (opposite side divided by the adjacent side)

Find the length side BD
---> by SOH (opposite side divided by the hypotenuse)

step 2
In the right triangle CDE
Find the length side CE
--> by CAH (adjacent side divided by the hypotenuse)
we have

substitute

Find the length side DE
--> by TOA (opposite side divided by the adjacent side)

step 3
Find the perimeter of the figure
The perimeter is equal to

substitute the values

Answer:
see below
Step-by-step explanation:
Any line between two points on the circle is a chord.
Any angle with sides that are chords and with a vertex on the circle is an inscribed angle.
Any angle with sides that are radii and a vertex at the center of the circle is a central angle. Each central angle listed here should be considered a listing of two angles: the angle measured counterclockwise from the first radius and the angle measured clockwise from the first radius.
<h3>1.</h3>
chords: DE, EF
inscribed angles: DEF
central angles: DCF . . . . . note that C is always the vertex of a central angle
<h3>2.</h3>
chords: RS, RT, ST, SU
inscribed angles: SRT, RSU, RST, RTS, TSU
central angles: RCS, RCT, RCU, SCT, SCU, TCU
<h3>3.</h3>
chords: DF, DG, EF, EG
inscribed angles: FDG, FEG, DFE, DGE
central angles: none
<h3>4.</h3>
chords: AE
inscribed angles: none
central angles: ACB, ACD, ACE, BCD, BCE, DCE