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3 years ago

10 x (150-3)=(10x150) ( _x3)

Mathematics

2 answers:

Vitek1552 [10]3 years ago

5 0

I'm not sure if it's 10x or 10 times a number

luda_lava [24]3 years ago

5 0

10 x (150-3) actually equals 1470
So we have to make (10 x 150) (_ x 3) = 1470
let's call the blank "a"

Now let's solve
(10 x 150) (a x 3) = 1470
10 times 150 equals 1500

1500 x (a x 3) = 1470
3 times a equals 3a because thats the correct way to write it.

1500 x 3a = 1470
-1500 -1500
Now subtract 1500 on both sides of the equal sign

3a = -30
3a ÷ 3 = -30 ÷ 3
1a = -10

Lastly divide 3 on both sides of the equal sign.

a = -10

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3 years ago

Which ordered pair would form a proportional relationship with the point graphed below? (60,-20)

valentina_108 [34]

Given:

The graphed point is (60,-20).

To find:

The ordered pair that would form a proportional relationship with the given point.

Solution:

If y is proportional to x, then

$y\propto x$

$y=kx$

$\dfrac{y}{x}=k$

Where, k is the constant of proportionality.

For the given point,

$k=\dfrac{-20}{60}$

$k=\dfrac{-1}{3}$

For option (A),

$k=\dfrac{30}{-10}$

$k=-3\neq \dfrac{-1}{3}$

For option (B),

$k=\dfrac{-15}{30}$

$k=-\dfrac{1}{2}\neq \dfrac{-1}{3}$

For option (C),

$k=\dfrac{10}{-30}$

$k=\dfrac{-1}{3}$ .

The point (-30,10) gives the same value of the constant of proportionality. So, the point (-30,10) forms a proportional relationship with the given point.

Therefore, the correct option is C.

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3 years ago

If 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), w

Yuliya22 [10]

The value of a is 80

Step-by-step explanation:

The distance of a point $(x_0,y_0)$ from the y-axis can be written as

$d_y = |x_0|$

because the x-coordinate of the y-axis is zero.

Similarly, the distance of a point $(x_0,y_0)$ from the x-axis can be written as

$d_x=|y_0|$

Since the y-coordinate of the x-axis is zero.

In this problem:

- The distance of the point A (−30, −45) from the y-axis can be written as

$d_A = |-30|=30$

- The distance of point B (a,a) from the x-axis can be written as

$d_B = |a| = a$

Since $a>0$ .

We are told that 2/3 of the distance from the y-axis to point A (−30, −45) is equal to 1/4 of the distance from the x-axis to point B(a, a), which means

$\frac{2}{3}d_A = \frac{1}{4}d_B$

Therefore,

$\frac{2}{3}(30)=\frac{1}{4}a$

And solving for a,

$20=\frac{1}{4}a\\a=80$

Learn more about distance:

brainly.com/question/3969582

#LearnwithBrainly

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3 years ago