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3 years ago

10

How do u solve 2x+5>13

1 answer:

Strike441 [17]3 years ago

8 0

You subtract 5 from that side and subtract 5 from 13 then it's 2x and 8 then divide by 2 so x is greater than 4.

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On your last credit card statement, you had a previous balance of $98.14, payments of $10, a periodic rate of 1.34 percent, and

a_sh-v [17]

New balance
98.14−10+(88.14×(0.0134÷12)+34.89
=123.13 .....answer

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3 years ago

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How far is football field to the park? *show your work*

nalin [4]

Answer:

10.95 miles

Step-by-step explanation:

$a = Park\ to\ Home\\\\b = Park\ to\ Football\ Field \\\\t_{h} = Park\ to\ Library\\\\t_{h} = \sqrt{a^{2} - 2^{2} } \\\\t_{h} = \sqrt{b^{2} - 10^{2} } \\\\b = \sqrt{12^{2} - a^{2} } \\\\-----------\\\\a^{2} - 2^{2} = 12^{2} - a^{2} - 10^{2} \\\\2a^{2} = 144 - 100 + 4 = 48 \\\\a = \sqrt{24} = 4.9\ miles \\\\-----------\\\\b = \sqrt{144 - 24} = \sqrt{120} = 10.95\ miles$

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4 years ago

Monthly sales of an SUV model are expected to increase at the rate of S′1t2 = -24t 1>3 SUVs per month, where t is time in mon

uysha [10]

The company will continue to manufacture this model for 19 months.

The question is ill-formatted. The understandable format is given below.

An SUV model's monthly sales are anticipated to rise at a rate of

$S'(t)=-24^{1/3}$ SUVs each month, where "t" denotes the number of months and "S(t)" denotes the monthly sales of SUVs. When monthly sales of 300 SUVs are reached, the business intends to discontinue producing this model.

Find S if monthly sales of SUVs are 1,200 at time t=0 (t). How long will the business keep making this model?

Given $S'(t)=-24^{1/3}$ ... ... (1)

Condition (1) at t=0; s(t) =1200

We find S(t)=300 then t=?

a) We find S(t)

from $S'(t)=-24^{1/3}$

$\implies \frac{dS(t)}{dt}=-24t^{1/3} ~~[\because X'(t)=\frac{dX}{dt} \\\implies dS(t) = -24t^{1/3}dt\\$

On Integrating both sides

$S(t)=-18t^{4/3}+c ~...~...~(2)$

Now, at t=0 then S(t)=1200

So, from (2)

1200=0+c

⇒c=1200

$\therefore$ from eq (2)

$S(t)=-18t^{4/3}+1200 ~...~...~(3)$

b) Considering that the firm intends to cease production of this model once monthly sales exceed 300 SUVs.

So, take S(t)=300

from eq (2) $300=-18t^{4/3}+1200$

$t^{4/3}=\frac{1200-300}{18}\\=\frac{900}{18}=50\\\implies t=50^{3/4}\\\implies t=18.8030$

Hence the company will continue 18.8020 months.

Learn more about integration here-

brainly.com/question/18125359

#SPJ10

8 0

2 years ago

The sum of two numbers is 300 and the two numbers have a ratio of 20:10.find the larger number

Stolb23 [73]

The larger number is 200. The ratio is 20:10 and 200 + 100 = 300.

4 0

4 years ago

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Someone help me with this!

JulijaS [17]

Answer:

63

Step-by-step explanation:

you have to add

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4 years ago

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