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Luda [366]
3 years ago
12

Need help with this!!

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

d

Step-by-step explanation:

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The trapezoid has one pair of parallel sides. 
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3 years ago
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Colton has watched 222 comedy movies for every 333 other movies. He has watched 303030 total movies.
Sedaia [141]

The total ratio is 5

The number of comedy movies watched is 12

The number of other movies watched is 18

<h3>What is a ratio?</h3>

Ratio is a comparison of two or more numbers that indicates their sizes in relation to each other. Therefore,

He has watched 2 comedy movies for every 3 other movies. The total movies he has watched is 30. Therefore,

  • 2:3

Ratio of comedy to total movies is as follows:

  • 2 : 5

number of comedy movies watched = 2 / 5 × 30 = 60 / 5 = 12

number of other movies watched = 3 / 5 × 30 = 90 / 5 = 18

Therefore,

total ratio = 5

number of comedy movies watched = 12

number of other movies watched = 18

learn more on ratios here: brainly.com/question/10080852

6 0
2 years ago
Slove the equation V=(20-2x)(15-2x)(x) for V
Schach [20]

Answer:

V = 300x + -70x2 + 4x3

Step-by-step explanation:

Simplifying

V = (20 + -2x)(15 + -2x)(x)

Reorder the terms for easier multiplication:

V = x(20 + -2x)(15 + -2x)

Multiply (20 + -2x) * (15 + -2x)

V = x(20(15 + -2x) + -2x * (15 + -2x))

V = x((15 * 20 + -2x * 20) + -2x * (15 + -2x))

V = x((300 + -40x) + -2x * (15 + -2x))

V = x(300 + -40x + (15 * -2x + -2x * -2x))

V = x(300 + -40x + (-30x + 4x2))

Combine like terms: -40x + -30x = -70x

V = x(300 + -70x + 4x2)

V = (300 * x + -70x * x + 4x2 * x)

V = (300x + -70x2 + 4x3)

Solving

V = 300x + -70x2 + 4x3

Solving for variable 'V'.

Move all terms containing V to the left, all other terms to the right.

Simplifying

V = 300x + -70x2 + 4x3

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3 years ago
Evaluate the function.<br> f(x) = -x^2 - 4x + 13<br> Find f(3)
julia-pushkina [17]

Answer: i believe the answer is 10

Step-by-step explanation:

3 0
3 years ago
Estimated quotient of 119÷23​
masha68 [24]

Answer:

5...................

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