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sergeinik [125]
2 years ago
10

PYTHAGORAS THEROM AND TRIGONOMETRY RATIO​

Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0

Answer:

1) ΔACD is a right triangle at C

=> sin 32° = AC/15

⇔ AC = sin 32°.15 ≈ 7.9 (cm)

2) ΔABC is a right triangle at C, using Pythagoras theorem, we have:

AB² = AC² + BC²

⇔ AB² = 7.9² + 9.7² = 156.5

⇒ AB = 12.5 (cm)

3)  ΔABC is a right triangle at C

=> sin ∠BAC = BC/AB

⇔ sin ∠BAC = 9.7/12.5 = 0.776

⇒ ∠BAC ≈ 50.9°

4) ΔACD is a right triangle at C

=> cos 32° = CD/15

⇔ CD = cos32°.15

⇒ CD ≈ 12.72 (cm)

Step-by-step explanation:

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Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

\star{ \sf{ \: let \: A(-3, 2) \: be \: (x1 \:, y1) \:  and  \: B(9, -3) \: be \: (x2 \:, y2) }}

\underline{ \sf{Finding \: the \: distance \: between \: the \: given \: points}} :

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\mapsto{ \sf{  \sqrt{ {(9 - ( - 3))}^{2} +  {( - 3 - 2)}^{2}  } }}

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\mapsto{ \sf{ \sqrt{ {(12)}^{2}  +  {( - 5)}^{2} } }}

\mapsto{ \sf{ \sqrt{144 + 25}}}

\mapsto{ \sf{ \sqrt{169} }}

\mapsto{ \sf{ \sqrt{ {(13)}^{2} } }}

\mapsto{ \sf{ 13 \: units}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

7 0
2 years ago
Please help! Question below (:
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The 3 inside angles of a triangle need to equal 180 degrees.


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The second on is adding 58 + 77 = 135 degrees.


X = 180 - 28 - 135 = 17 degrees

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C is the answer

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