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bixtya [17]
3 years ago
9

If B is the midpoint of AC. AB = 4v and AC = 5v + 24. what is BC?

Mathematics
1 answer:
inysia [295]3 years ago
5 0

Answer:

v+24

Step-by-step explanation:

I first drew a line with A in one side and C in the other side. Then, I put B in the middle, as it is the midpoint. Under AB, I put 4v, and under AC, I put 5v+24. To get BC, you must subtract 5v+24 and 4v. I did 5v+24-4v. All I really had to do was subtract 4v from 5v which gave me v, since I can only subtract like-term numbers. Anyway, after that, I got v+24. Hope this helped!

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<h3>Speed and distance of an object</h3>

If a certain car going 60 mph can stop in 180 ft, then we can express this as:

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To determine the speed for a car traveling at 100ft, we will have:

  • x = 100ft

Take the ratio of the expression

60/x = 180/100
180x = 6000

x = 33.3mph

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2 years ago
The proof for the power property of logarithms appears in the table with an expression missing. Which expression is missing from
Gwar [14]

Answer:

C.) log(b^x-y)

Step-by-step explanation:

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3 years ago
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3 years ago
Use y = 16x^2 to complete the table.<br> What pattern (symmetry) do you notice from the table?
KATRIN_1 [288]

Answer:

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y = 16*x^2

For example in the first slot, we have x = -4

Then we will have:

y = 16*(-4)^2 = 240

Then we complete the empty slot with 240.

The table would be:

\left[\begin{array}{cccccccccccccccc}x&-4&-3&-2.5&-2&-1.5&-1&-0.5&0&0.5&1&1.5&2&2.5&3&4\\y&240&\end{array}\right]

Now we just need to do the same for the other values:

y(-3) = 16*(-3)^2 = 144

y(-2.5) = 16*(-2.5)^2 = 100

y(-2) = 16*(-2)^2 = 64

y(-1.5) = 16*(-1.5)^2 = 36

y(-1) = 16*(-1)^2 = 16

y(-0.5) = 16*(-0.5)^2 = 4

y(0) = 16*(0)^2 = 0

y(0.5) = 16*(0.5)^2 = 4

y(1) = 16*(1)^2 = 16

y(1.5) = 16*(1.5)^2 = 36

y(2) = 16*(2)^2 = 64

y(2.5) = 16*(2.5)^2 = 100

y(3) = 16*(3)^2 = 144

y(4) = 16*(4)^2 = 240

Then the complete table is:

\left[\begin{array}{cccccccccccccccc}x&-4&-3&-2.5&-2&-1.5&-1&-0.5&0&0.5&1&1.5&2&2.5&3&4\\y&240&144&100&64&36&16&4&0&4&16&36&64&10&144&240\end{array}\right]

Then we can see that there is a symmetry around the value x = 0.

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