Answer:
64√2 or 64 StartRoot 2 EndRoot
Step-by-step explanation:
A 45-45-90 traingle is a special traingle. Let's say one of the leg of the triangle is x. The other one is also x because of the isosocles triangle theorem. Therefore, using the pytagorean theorem, you find that x^2+x^2=c^2. 2(x)^2=c^2. You then square root both sides and get c= x√2.
Therefore, the two legs are x and the hypotenuse is x√2. x√2=128 because the question says that the hypotenuse is 128. Solve for x by dividing both sides by √2. X=128/√2. You rationalize it by multiplying the numberator and denominator of the fraction by √2. √2*√2= 2.
X=(128√2)/2= 64√2 cm.
Since X is the leg, the answer would be 64√2
Answer:
I think the figure of N and E of 48in is 2304. The figure of I and E and N and A of 32in is 1024. The figure of L and I and L and A is 144.
Step-by-step explanation:
To find the area, you have to multiply of each side in each figure. For example, Figure A and B and C and D of 16in is 16 × 16 which is 256.
A = Area
a = Side
A = 2304, A = a^2 = 48^2 = 2304.
A = 1024, A = a^2 = 32^2 = 1024.
A = 144, A = a^2 = 12^2 = 144.
I hope this answers your question!
The slope is 3/1, which can be simplified to 3. Find it by traveling up 3 points and over 1 point form one intersection point to the next.
