<u>Answer:</u>
<em>int fNumber,scndNumber = -1, </em>
<em>dup = 0;
</em>
<em>do {
</em>
<em>cin >> fNumber;
</em>
<em>if ( scndNumber == -1) {
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>else {
</em>
<em>if ( scndNumber == fNumber )
</em>
<em>duplicates++;
</em>
<em>else
</em>
<em>scndNumber = fNumber;
</em>
<em>}
</em>
<em>} while(fNumber > 0 ); </em>
<em>cout << dup;
</em>
<u>Explanation:</u>
Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>
<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.
Answer:
Option d is the correct answer for the above question.
Explanation:
- WAN is a type of network that facilities network connection all over the world. It can connect every computer which is in anywhere in the world while the other technology like LAN and MAN is used for small area locations.
- The above question asked that about that statement which is not the property of WAN and that is option d because it states that WAN is used to connect only small areas of computers, but it can connect all the computers of the world, while the other property is valid for WAN.
The second factor as it did not make travel easy at all
Answer:
Following are the solution to this question:
Explanation:
This algorithm uses the divide and rule approach works, which splits the list into two sublists depending on if they are smaller or larger than the pivotal factor. It has O(n*log n) complexity.
It splits down the list in more than one version frequently till every sublist becomes based on a single element and fuses it to offer an ordered array. The merge type works according. It has O(n*log n) complexity.
Please find the attachment file of the sorting.
Answer:
Refer below.
Explanation:
VPC, Subnets, Route Table(s), Nat Gateway, and Internet Gateway. These are the least required services to provide internet access to a private EC2 instance. NAT gateway requires an internet gateway.
