Answer:
x= - AB-4/5 and No Solution
False for all xER
Step-by-step explanation:
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
531.167 ft²
Step-by-step explanation:
Given data
Dimension of pool
Diameter =24ft
Radius =12ft
If the cover must hang by 1ft around, then the diameter is 26ft
Radius =13ft
Area of cover = πr²
Substitute
Area = 3.142*13²
Area =3.143*169
Area =531.167 ft²
Hence the minimum area is 531.167 ft²
Answer:
14 years
Step-by-step explanation:
£280 is 7% of 4000 so £4000 euro more would be 4000/280 = 14
Lets solve this step by step.
8 * 8 = 64
Lets suppose there are 8 aquariums and there are 8 fish in each. Therefore, there are 8 groups of 8 fish. Add and solve.
8+8+8+8+8+8+8+8 = 64
