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Marrrta [24]
3 years ago
6

Help me plz ill give brainiest

Mathematics
2 answers:
Maslowich3 years ago
8 0

Answer:

1 is 3.25

Step-by-step explanation:

sergij07 [2.7K]3 years ago
4 0
Week 0 he practices 0 hours
week 1 he practices 3.25 hours
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A system has one each of two different types of components in joint operation. Let X and Y denote the random lengths of the live
RSB [31]

Answer:

The value of E(Y/X) is 2.

Step-by-step explanation:

As the complete question is not given, thus the complete question is found online and is attached herewith.

So the joint density function is given as

f(x,y)=\left \{ {{\dfrac{x}{8}e^{-\dfrac{x+y}{2}}    \,\,\,\,0 \leq x,0\leq y \atop {0}} \right.

So the marginal function for X is given as

f_x=\int\limits^{\infty}_0 {f(x,y)} \, dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x+y}{2} }dy\\f_x=\int\limits^{\infty}_0 \dfrac{x}{8}e^{-\frac{x}{2}}e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{8}e^{-\frac{x}{2}}\int\limits^{\infty}_0e^{-\frac{y}{2} }dy\\f_x= \dfrac{x}{4}e^{-\frac{x}{2}}

Now

f(Y/X)=\dfrac{f(X,Y)}{f(X)}\\f(Y/X)=\dfrac{\dfrac{x}{8}e^{-\frac{x+y}{2} }}{\dfrac{x}{4}e^{-\frac{x}{2}}}\\f(Y/X)=\dfrac{1}{2}e^{-\frac{y}{2} }

Now the value of E(Y/X) is given as

E(Y/X)=\int\limits^{\infty}_0 {yf_{Y/X}} \, dy \\E(Y/X)=\int\limits^{\infty}_0 {y\dfrac{1}{2}e^{-\frac{y}{2} } }\, dy\\E(Y/X)=\dfrac{1}{2}\dfrac{\sqrt{2}}{(\dfrac{1}{2})^2}=2

So the value of E(Y/X) is 2.

3 0
3 years ago
If your bank charges an out-of-network service fee of $3.00, and you withdraw $20 from each of three out-of-network ATMs, how mu
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It is $69 because if every time you withdraw money you get $3 and you took $20 out 3 times that 20x3 is 60 and then plus $3x3 is nine add it all together it is $69
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A circle with radius 3 has a sector with a central angle of 1/9 pi radians
Art [367]

The area of sector is 1.57 m²

<u>Explanation:</u>

Given:

Radius, r = 3 m

Central angle of a sector = 1/9π radians

Area of sector, A = ?

We know:

Area of sector, A = \frac{1}{2} r^2 \alpha

where,

α is the central angle in radians

On substituting the value we get:

A = \frac{1}{2} X(3)^2 X \frac{1}{9}X 3.14\\ \\A = 1.57 m^2

Therefore, the area of sector is 1.57 m²

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