Answer:
The equivalent statement is
⇒ 2nd answer
Step-by-step explanation:
* Lets explain how to solve the problem
- Any root can be a fraction power
- Ex: 
![\sqrt[3]{a}=a^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[4]{a}=a^{\frac{1}{4}}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D)
![\sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
* The expression is 
∵
can be written as 
∵ ![(80)^{\frac{1}{4}}=\sqrt[4]{80}](https://tex.z-dn.net/?f=%2880%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3D%5Csqrt%5B4%5D%7B80%7D)
∴
= ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
* The equivalent statement is ![(\sqrt[4]{80})^{x}](https://tex.z-dn.net/?f=%28%5Csqrt%5B4%5D%7B80%7D%29%5E%7Bx%7D)
Answer:
x = 4
Step-by-step explanation:
6(6 + x) = 5(5 + x + 3) => secant secant theorem
36 + 6x = 5(8 + x)
36 + 6x = 40 + 5x
Subtract 36 from each side
36 + 6x - 36 = 40 + 5x - 36
6x = 4 + 5x
Subtract 5x from each side
6x - 5x = 4 + 5x - 5x
x = 4
Answer:
the answer should be A
Step-by-step explanation:
be your X values are not supposed to repeat
Answer:
x = 9
y = 9
Step-by-step explanation:
Given :
Let :
Kenyan French roast coffee = x
Cost per x = $8
Sumatran Coffee = y
Cost per y = $10
x + y = 18 - - - - (1)
8x + 10y = 9 * 18 ;
8x + 10y = 162 - - - - (2)
From (1):
x = 18 - y
Put x = 18 - y in (2)
8(18 - y) + 10y = 162
144 - 8y + 10y = 162
2y = 162 - 144
2y = 18
y = 9
x = 18 - y
x = 18 - 9
x = 9