Given Triangle DEF is isosceles and angle D is the vertex angle, Find x, DE, DF, EF
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Answer:
The width of the walkway is 4 feet.
Step-by-step explanation:
The garden and a walkway around its perimeter have an area of 460 square feet.
The length of the garden = 15 feet
The width of the garden = 12 feet
Assuming that walkway is of uniform width, we can solve the following equation.
Expanding this we get;
We will solve this using quadratic equation formula:
Here a = 4 , b = 54 , c = -280
We get the roots as x = 4 and x =
Neglecting the negative value, we will take x = 4 feet.
Hence, the width of the walkway is 4 feet.