Are you solving the inequality
8 x/3 apply the formula x power/root. Hope that helped!
What he said bro and it right Ik
Answer:
Function H h(t) = -6.1 + 19t - 55
Step-by-step explanation:
Let t = 1
<u>Function F</u>
h(t) = 6.1t^2 + 19t - 54.4
h(1) = 6.1(1)^2 + 19(1) - 54.4
h(1) = 6.1 + 19 - 54.4
h(1) = -29.3
<u>Function G</u>
h(t) = -24.1t^2 + 2.8
h(1) = -24.1(1)^2 + 2.8
h(1) = -24.1 + 2.8
h(1) = -21.3
<u>Function H</u>
h(t) = -6.1t^2 + 19t - 55
h(1) = -6.1(1)^2 + 19(1) - 55
h(1) = -6.1 + 19 - 55
h(1) = -42.1
<u>Function J</u>
h(t) = -6.1t^2 + 19t + 0.99
h(t) = -6.1(1)^2 + 19(1) + 0.99
h(t) = -6.1 + 19 + 0.99
h(t) = 13.89
What we know:
Shape is square
Area= 150 cm²
Area=s²
What we need to find: s=side of square
Area=s²
150=s²
√150=√s²
√150=s
s≈12 cm
C. 12cm
Remember when finding the square root of a number you get a positive and negative solution. In this case, length is positive so we do not need the negative solution.