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KonstantinChe [14]
3 years ago
11

A right cylinder with radius 4 cm and height 3 cm

Mathematics
1 answer:
SSSSS [86.1K]3 years ago
5 0

Answer:

Step-by-step explanation:

V=\pi r^2h=\pi *4^2*3\\=150.79645cm^3\\A=2\pi rh+2\pi r^2=2*\pi *4*3+2*\pi *4^2\\=175.93cm^2

I put both volume and area

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If x -1/7,evaluate x²+1/x²​
SCORPION-xisa [38]

Answer:

given \: x =  -  \frac{1}{7}

x {}^{2}  +  \frac{1}{x {}^{2} }

(  - \frac{1}{7} ) {}^{2}  +  \frac{1}{  (  - \frac{1}{7} ) {}^{2} }

\frac{1}{49}  +  \frac{1}{ \frac{1}{49} }

\frac{1}{49}  +  \frac{1 \times 49}{1}

\frac{1}{49}  + 49

\frac{2402}{49}  \: or \: 49.02

6 0
3 years ago
A bank advertises that it compounds money quarterly and that it will take Double your money in 10 years. what is the interest-ra
S_A_V [24]

The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.

Step-by-step explanation:

The given is,

                          Compounds money quarterly

                          Double your money in 10 years

Step:1

              Formula to calculate future investment with compounded quarterly,

                                                        A =P(1+\frac{r}{n} )^{nt}...............................(1)

              Where, A - Future amount

                           P - Initial investment\

                            r - Rate of interest

                            n - No. of compounding in a year

                             t - No. of years

Step:2

               Let, P = X

                      A = 2X ( Double your money )

              From given, n - 4 ( for compounding quarterly )

                                    t - 10 years

               From equation (1)

                                                        2X =X(1+\frac{r}{4} )^{(4)(10)}

                                                         \frac{2X}{X}  =(1+\frac{r}{4} )^{(4)(10)}

                                                            2  =(1+\frac{r}{4} )^{40}

          Take root 40^{th} root on both side,

                                                         \sqrt[40]{2} = (1+\frac{r}{4} )

                                            1.017479692 = (\frac{4+r}{4} )

                                     (1.017479692)(4) = (r+4)

                                                  4.06992=(r+4)

                                                              r = 4.06992 -4

                                                              r =( 0.06992)(100)

                                                              r = 6.992 %

Result:

             The interest rate is 6.992%, if a bank advertises that it compounds money quarterly and that it will take Double your money in 10 years.

3 0
3 years ago
A circular running track is 1/2 mile long. Elena runs on this track, completing each lap in 1/10 of an
fomenos
The answer might be wrong but
3 0
3 years ago
Read 2 more answers
Item 15
blsea [12.9K]
The right question is that the lowest altitute is 3^8 feet

You are told that the highest altitude is 3 times the lowest altitude =>

highest altitude = 3 * lowest altitude = 3 * 3^8 feet.

Now you use the ruel of mutiplication of powers with the same base: copy the base and sum the exponents => 3 * 3^8 = 3 ^(1+8) = 3^9.

Note: remember that 3 = 3^1.

Answer: 3^9 feet
8 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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