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Sloan [31]
3 years ago
6

FIND THE VOLUME OF A CONE 0F DIAMETER 14M AND HEIGHT 21CM. (TAKE = 3 )

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

343π

Step-by-step explanation:

To find the volume of a cone, we have to use this formula

\frac{1}{3} × π × r² × h

Where 'r' is the radius and 'h' is the height

Let's start putting in the value's

We have diameter but in the formula we need the radius so we half the diameter to get the radius so 14 ÷ 2 = 7

\frac{1}{3} × π × r² × h

\frac{1}{3} × π × 7² × 21

→  Simplify the expression

\frac{1}{3}  × π × 49 × 21

→ Simplify it further

343π

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Question: A box of chocolates contains square chocolates, which weigh 10 g each, and round chocolates, which weigh 8 g each. The
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Answer: the box contained 9 square chocolates and 15 round chocolates.

Step-by-step explanation:

Let x represent the number of square chocolates contained in the box.

Let y represent the number of round chocolates contained in the box.

The box of chocolates contains square chocolates, which weigh 10g each and round chocolates which weigh 8g each. The combined weight of all the chocolates is 210g. It means that

10x + 8y = 210- - - - - - - - - - -1

The number of round chocolates is 3 less than twice the number of square chocolates. It means that

y = 2x - 3

Substituting y = 2x - 3 into equation 1, it becomes

10x + 8(2x - 3) = 210

10x + 16x - 24 = 210

26x = 210 + 24

26x = 234

x = 234/26

x = 9

y = 2x - 3 = 2 × 9 - 3

y = 18 - 3

y = 15

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3 years ago
I need the answer. (will give brainliest)
WINSTONCH [101]

Answer:

30 degrees

Step-by-step explanation:

add the two together then subtract 180

4 0
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AN ice cream factory makes 230 quarts of ie cream in 2 hours. how many quarts could be made in 12 hours?what was the rate per da
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3 years ago
Please help me out with this please
ki77a [65]

Answer:

P = 9 is the max value

Step-by-step explanation:

Sketch

2x + 4y = 10

with x- intercept = (5, 0) and y- intercept (0, 2.5)

x + 9y = 12

with x- intercept = (12, 0) and y- intercept = (0, \frac{4}{3} )

Solve

2x + 4y = 10 and x + 9y = 12 to find the point of intersection at (3, 1)

The region corresponding to the solution of the system of constraints

Has vertices at (0, \frac{4}{3}), (0, 0) , (5, 0) and (3, 1)

Now evaluate the objective function at each vertex.

(0, 0) can be excluded as it will not give a maximum

(5, 0) → P = 5 + 0 = 5

(0, \frac{4}{3}) → 0 + 8 = 8

(3, 1) → 3 + 6(1) = 3 + 6 = 9 ← maximum value

Thus the maximum value is 9 when x = 3 and y = 1

7 0
3 years ago
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