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Sloan [31]
3 years ago
6

FIND THE VOLUME OF A CONE 0F DIAMETER 14M AND HEIGHT 21CM. (TAKE = 3 )

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
6 0

Answer:

343π

Step-by-step explanation:

To find the volume of a cone, we have to use this formula

\frac{1}{3} × π × r² × h

Where 'r' is the radius and 'h' is the height

Let's start putting in the value's

We have diameter but in the formula we need the radius so we half the diameter to get the radius so 14 ÷ 2 = 7

\frac{1}{3} × π × r² × h

\frac{1}{3} × π × 7² × 21

→  Simplify the expression

\frac{1}{3}  × π × 49 × 21

→ Simplify it further

343π

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Hi There!

Step-by-step explanation and Answer:

21 * 0.2 = $4.2 (Discount)

21 - 4.2 = $16.8 (Sale Price)

Hope This Helps :)

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What is the equation of the line in slope intercept form using these points?
deff fn [24]

Answer:

y = -x - 1

Step-by-step explanation:

1. The slope-intercept form of any linear equation is y = mx + b, where y = y-coordinate, m = slope, x = x-coordinate, and b = y-intercept.

2. To find the slope given two points, we can use the formula \frac{y_2-y_1}{x_2-x_1} and plug in the corresponding variable.

  • \frac{5-(-2)}{-6-1}
  • \frac{5+2}{-7}
  • \frac{7}{-7}
  • -1

3. Okay, so the slope is -1x or just -x. This means that the equation looks like this so far: y = -x + b

4. To find b, the y-intercept, we can take the equation of b = y_1 - m * x_1 and plug in the values!

  • b = -2-(-1)*1
  • b = -2 + 1 * 1
  • b = -1 * 1
  • b = -1

5. Now that we have our y-intercept and slope, let's plug in those values and find the equation!

  • y = -x - 1

Therefore, the equation of the line is y = -x - 1. I hope this helped you!

3 0
2 years ago
Complete the square to write the quadratic expression in vertex form.
Anvisha [2.4K]

Answer:

1. (x - 3)² = 8

2. (x + 2)² = 3

3. (x + 6)² = $ \frac{101}{2} $

4. (x + 3)² = 27

5. (x + 4)² = 13

6.  $ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $

Step-by-step explanation:

Completion of Square: $ (x - a) ^2 = x^2 - 2ax + a^2 $

In the following problems the terms in the RHS of the above equation may be missing. We balance the equation. Simplify it and re write it in terms of LHS.

1. x² - 6x + 1 = 0

Taking the constant term to the other side, we get:

x² - 6x = - 1

⇒ x² - 2(3)x = -1

⇒ x² -2(3)x + 9 = - 1 + 9  [Adding 9 to both the sides]

⇒ x² -2(3)x + 3² = 8

⇒ (x - 3)² = 8 is the answer.

2. 3x² + 12x + 3 = 0

Note that the co-effecient of x² is not 1. We make it 1, by dividing the whole equation by 3. And then proceed like the previous problem.

3x² + 12x = -3

Dividing by 3 through out, x² + 4x = - 1

⇒ x² + 2(2) + 4 = -1 + 4

⇒ x² +2(2) + 2² = 3

⇒ (x + 2)² = 3 is the answer.

3. 2x² + 24x = 29

x² + 12x = $ \frac{29}{2} $

⇒ x² + 2(6)x + 36 = $ \frac{29}{2} $ + 36

⇒ x² + 2(6)x + 6² = $ \frac{29 + 72}{2} $

⇒ (x + 6)² = $ \frac{101}{2} $ is the answer.

4. x² + 6x - 18 = 0

x² + 6x = 18

⇒ x² + 2(3)x = 18

⇒ x² + 2(3)x + 9 = 18 + 9

⇒ x² + 2(3)x + 3² = 27

⇒ (x + 3)² = 27 is the answer.

5. x² + 8x + 3 = 0

x² + 8x = -3

⇒ x² + 2(4)x = -3

⇒ x² + 2(4)x + 16 = - 3 + 16

⇒ x² + 2(4)x + 16 = 13

⇒ (x + 4)² = 13 is the answer.

6. 9x² - 30x + 6 = 0

9x² - 30x = - 6

⇒ x² $ - \frac{30}{9} $ x = - 6

$ \implies x^2 -2 \bigg( \frac{15}{9} \bigg )x + \frac{225}{81} = - 6 + \frac{225}{81} $

$ \implies x^2 - 2\bigg( \frac{15}{9} \bigg ) x + \bigg ( \frac{15}{9} \bigg ) ^2 = \frac{261}{81} $

$ \bigg( x - \frac{15}{9} \bigg) ^2 = \frac{261}{81} = \frac{29}{9} $ is the answer.

6 0
3 years ago
The weight of an object on the moon varies directly as its weight on Earth. With all of his gear on, Neil Armstrong weighed 360
babymother [125]

amistre64 Medals 0
e = k.m
360 = k.60
k = 360/60 = 36/6 = 6
108 = 6.m
108/6 = m = 18 
8 0
3 years ago
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