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aleksandrvk [35]

3 years ago

14

The dot plot shows the number of goals that the Springlane High School soccer team scored per game last season. How many games d

id the team play?

2 answers:

Dima020 [189]3 years ago

4 0

There is no dot plot so i can't tell

viktelen [127]3 years ago

4 0

Answer:

Step-by-step explanation:

it shows 16 dots but it keeps saying i get it wrong

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Which inequality defines the problem below ?

Likurg_2 [28]

Answer:

D

Step-by-step explanation:

so total travel by x bikers = 50 multiplied by x = 50x

According to the question

50x = 560

dividing 560 miles by 50 miles per biker give ya 11.2 or approximately 12 bikers.

7 0

3 years ago

What value of $k$ will make $4x^2 - 20x + k$ the square of a binomial?

Arisa [49]

Answer:

k = 25

Step-by-step explanation:

(2x - sqrt(k) )^2 Expand this as a binomial

4x^2 - 4x*sqrt(k) + k The middle term must be -20x Solve for k so it is

-4xsqrt(k) = - 20x Divide by -4x

sqrt(k) = -20x/-4x Do the division

sqrt(k) = 5 Square both sides

k = 25

5 0

3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$

The degrees of freedom for this sample size are:

$df=n-1=50-1=49$

The t-value for a 95% confidence interval and 49 degrees of freedom is t=2.01.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_M=2.01 \cdot 0.305=0.61$

Then, the lower and upper bounds of the confidence interval are:

$LL=M-t \cdot s_M = 6.34-0.61=5.73\\\\UL=M+t \cdot s_M = 6.34+0.61=6.95$

The 95% confidence interval for the mean is (5.73, 6.95).

4 0

3 years ago

Which pair of expressions below are equivalent?

Ede4ka [16]

Answer:

The answer is C

Hope this helped!

7 0

2 years ago

Find the difference 10 - ( – 25 )

sergey [27]

There is no difference they are both negative numbers or we could say 25 is higher number then 10 but it negative

5 0

3 years ago

Read 2 more answers