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3 years ago

29 is 6 more than k. Solve for k. Make an equation for k.

Mathematics

2 answers:

Snowcat [4.5K]3 years ago

7 0

Answer:

Step-by-step explanation:

29 minus 6 equals 23

Dominik [7]3 years ago

6 0

Answer:

k = 23

29 = k + 6

Step-by-step explanation:

29 = k + 6

k = 29 - 6

k = 23

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horrorfan [7]

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3 years ago

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Answer:

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Luba_88 [7]

Answer:

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Step-by-step explanation:

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3 years ago

Solve the system substitution y= 4x + 1 and 3x+2y =13

strojnjashka [21]

Given :

${\qquad \sf \dashrightarrow y= 4x + 1 \: –––– \sf \: (i)}$

${\qquad \sf \dashrightarrow 3x + 2y = 13 \: –––– \sf \: (ii)}$

Now, Substituing the value of y in equation (ii) :

${\qquad \sf \dashrightarrow \: 3x + 2y = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 2(4x + 1) = 13 }$

${\qquad \sf \dashrightarrow \: 3x + 8x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x + 2 = 13 }$

${\qquad \sf \dashrightarrow \: 11x = 13 - 2 }$

${\qquad \sf \dashrightarrow \: 11x = 11 }$

${\qquad \sf \dashrightarrow \: x = \dfrac{11}{11} }$

${\qquad \sf \dashrightarrow \bf \: x = 1 }$

Now, substituting the value of x in equation (i) :

${\qquad \sf \dashrightarrow y= 4x + 1}$

${\qquad \sf \dashrightarrow y= 4(1) + 1}$

${\qquad \sf \dashrightarrow y= 4 + 1}$

${\qquad \bf \dashrightarrow y= 5}$

8 0

2 years ago

1 1\4x2 1\5 ≤ ≥ = 5\6 x 2 1\5

ValentinkaMS [17]

Answer:

≥

Step-by-step explanation:

1 1\4x2 1\5 = 2 3/4

5/6 x 2 1/5 = 1 5/6

7 0

3 years ago