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2 years ago

ASAP PLZ HELP WILL MARK BRAINLIST IF U WANT TO FIRST PERSON WHO ANSWERS RIGHT

Mathematics

2 answers:

photoshop1234 [79]2 years ago

8 0

Answer:

15.0

Step-by-step explanation:

Square root entire equation (-8 - 7)^2 + (-5 + 4)^2

shutvik [7]2 years ago

7 0

I got 11.4.

I used the distance formula subtracted 7 from -4 and squared it and got 121 and then subtracted -8 from -5, two negative equal positive. Squared it and got 9. Added them together then found the square root. I could be wrong though since someone else got a different answer. You can try out the problem yourself to check over.

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PLZZZZZZZZZZ HELP ME WITH THIS

Pavlova-9 [17]

Answer:

First answer:

-16y=-19x+12

16y=19x-12

y=19/16x-3/4

Second answer:

8y=-15x-9

y=-15/8x-9/8

7 0

2 years ago

Which equation shows y=3/4x−52 in standard form? 4x−3y=10 4x−3y=−10 3x−4y=10 3x−4y=−10

snow_tiger [21]

Y = 3/4x - 5/2....subtract 3/4x from both sides
-3/4x + y = -5/2 ....multiply everything by common denominator of 4
-3x + 4y = -10

4 0

2 years ago

Y=1/4 (x+2)(x – 6

gladu [14]

I have no idea I’m answering this because I need to ask more questions

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2 years ago

Identify the coordinates for point B. Type your answer in the form (#,#), without spaces.

neonofarm [45]

Answer:

point B = (3,-2)

Step-by-step explanation:

7 0

2 years ago

A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .

Eduardwww [97]

Answer: $\bold{S_{\infty}=\dfrac{3125}{2}=1562.5}$

<u>Step-by-step explanation:</u>

a₁, 375, a₃, a₄, 81

First, let's find the ratio (r). There are three multiple from 375 to 81.

$375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}$

Next, let's find a₁

$a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625$

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

$S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}$

7 0

2 years ago