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4 years ago

Solve this inequality. -9x - 3 > 51

Mathematics

1 answer:

aalyn [17]4 years ago

4 0

Answer:

x<-6

Step-by-step explanation:

add 3 to 51, then divide by -9 and switch the symbol

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How many days would it take a construction loan of $548,048 to earn$50,000 exact interest at 9% interest rate?

san4es73 [151]

$\bf \qquad \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &50000\\
P=\textit{original amount deposited}\to& \$548048\\
r=rate\to 9\%\to \frac{9}{100}\to &0.09\\
t=years
\end{cases}
\\\\\\
50000=548048\cdot 0.09t\implies \cfrac{50000}{0.09(548048)}=t\implies 1.014\approx t$

8 0

3 years ago

Read 2 more answers

3c/4 - 2c/4 = 4 (solve with work please)

xxMikexx [17]

Simplifying

2c + 3 = 3c + -4

Reorder the terms:

3 + 2c = 3c + -4

Reorder the terms:

3 + 2c = -4 + 3c

Solving

3 + 2c = -4 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.

3 + 2c + -3c = -4 + 3c + -3c

Combine like terms: 2c + -3c = -1c

3 + -1c = -4 + 3c + -3c

Combine like terms: 3c + -3c = 0

3 + -1c = -4 + 0

3 + -1c = -4

Add '-3' to each side of the equation.

3 + -3 + -1c = -4 + -3

Combine like terms: 3 + -3 = 0

0 + -1c = -4 + -3

-1c = -4 + -3

Combine like terms: -4 + -3 = -7

-1c = -7

Divide each side by '-1'.

c = 7

Simplifying

c = 7

3 0

3 years ago

PLEASE HELP I WILL MARK YOU BRAINLIEST PLEASE AND SHOW YOUR WORK (1) Jaime has 103 toys. He can fit a maximum of 9 toys into eac

Artist 52 [7]

Answer:

(1) 12 boxes (2) 1173 points

Step-by-step explanation:

(1) Jamie needs to fit all if his toys in the boxes, so you would need to do 103 times 9, making it 11.4. So, you'd need twelve boxes to fit all of he toys into boxes.

(2) The contestant earned 69 points, and each of those points are worth 17 points, meaning you have to do 17 times 69, which is 1173 .

3 0

4 years ago

Difference between real numbers and intergers

Greeley [361]

Answer:

REAL NUMBER - real number is union of rational and irrational numbers .... whole numbers, natural numbers, integers, rational and irrational numbers are included in real numbers.

INTEGER -. integer means

means whole - valued positive or negative number or 0......

suppose 1, 2, 3, -6, -2....

whole numbers, such as 3, 4, but not 3.6 or √4 .

I hope you understand the difference between real numbers and integers.......

4 0

3 years ago

John, Joe, and James go fishing. At the end of the day, John comes to collect his third of the fish. However, there is one too m

Dmitry [639]

Answer:

The minimum possible initial amount of fish: $52$

Step-by-step explanation:

Let's start by saying that

$x$ = is the initial number of fishes

John:

When John arrives:

he throws away one fish from the bunch

$x-1$

divides the remaining fish into three.

$\dfrac{x-1}{3} + \dfrac{x-1}{3} + \dfrac{x-1}{3}$

takes a third for himself.

$\dfrac{x-1}{3} + \dfrac{x-1}{3}$

the remaining fish are expressed by the above expression. Let's call it John

$\text{John}=\dfrac{x-1}{3} + \dfrac{x-1}{3}$

and simplify it!

$\text{John}=\dfrac{2x}{3} - \dfrac{2}{3}$

When Joe arrives:

he throws away one fish from the remaining bunch

$\text{John} -1$

divides the remaining fish into three

$\dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3} + \dfrac{\text{John} -1}{3}$

takes a third for himself.

$\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

the remaining fish are expressed by the above expression. Let's call it Joe

$\text{Joe}=\dfrac{\text{John} -1}{3}+ \dfrac{\text{John} -1}{3}$

and simiplify it

$\text{Joe}=\dfrac{2}{3}(\text{John}-1)$

since we've already expressed John in terms of x, we express the above expression in terms of x as well.

$\text{Joe}=\dfrac{2}{3}\left(\dfrac{2x}{3} - \dfrac{2}{3}-1\right)$

$\text{Joe}=\dfrac{4x}{9} - \dfrac{10}{9}$

When James arrives:

We're gonna do this one quickly, since its the same process all over again

$\text{James}=\dfrac{\text{Joe} -1}{3}+ \dfrac{\text{Joe} -1}{3}$

$\text{James}=\dfrac{2}{3}\left(\dfrac{4x}{9} - \dfrac{10}{9}-1\right)$

$\text{James}=\dfrac{8x}{27} - \dfrac{38}{27}$

This is the last remaining pile of fish.

We know that no fish was divided, so the remaining number cannot be a decimal number. <u>We also know that this last pile was a multiple of 3 before a third was taken away by James</u>.

Whatever the last remaining pile was (let's say $n$ ), a third is taken away by James. the remaining bunch would be $\frac{n}{3}+\frac{n}{3}$

hence we've expressed the last pile in terms of n as well. Since the above 'James' equation and this 'n' equation represent the same thing, we can equate them:

$\dfrac{n}{3}+\dfrac{n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

$\dfrac{2n}{3}=\dfrac{8x}{27} - \dfrac{38}{27}$

L.H.S must be a Whole Number value and this can be found through trial and error. (Just check at which value of n does 2n/3 give a non-decimal value) (We've also established from before that n is a multiple a of 3, so only use values that are in the table of 3, e.g 3,6,9,12,..

at n = 21, we'll see that 2n/3 is a whole number = 14. (and since this is the value of n to give a whole number answer of 2n/3 we can safely say this is the least possible amount remaining in the pile)

$14=\dfrac{8x}{27} - \dfrac{38}{27}$

by solving this equation we'll have the value of x, which as we established at the start is the number of initial amount of fish!

$14=\dfrac{8x}{27} - \dfrac{38}{27}$

$x=52$

This is minimum possible amount of fish before John threw out the first fish

8 0

3 years ago