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11Alexandr11 [23.1K]
3 years ago
13

Mike purchased a round wall clock the clocks radius is 10m what is the circumference of the clock

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0

Answer:

62.8 m

Step-by-step explanation:

The circumference of the clock is the circumference of a circle which is given by

2 Pi r

Where

Pi = 3.14

Radius r = 10m

Therefore

Circumference = 2 x 3.14 x 10

= 62.8 m

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4a=23 Solve the equation. 4a=23 a=
REY [17]

Answer:

4a=23

4a/4 = 23/4

a=5.75

Step-by-step explanation:

6 0
3 years ago
&lt;x and &lt;y are supplementary angles.&lt;y measures 97° what is the measurement for &lt;x?<br>​
Ilia_Sergeevich [38]

Answer:

It’s 83 degrees

Step-by-step explanation:

180-97=83, it’s 180 because 180 is a supplementary angle.

4 0
3 years ago
(1 point) A fish tank initially contains 15 liters of pure water. Brine of constant, but unknown, concentration of salt is flowi
Drupady [299]

Answer:

a. \dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. x(t) = 6\frac{2}{3} \cdot c \cdot t

c. c  = \dfrac{3}{8}  \ g/L

Step-by-step explanation:

a. The volume of water initially in the fish tank = 15 liters

The volume of brine added per minute = 5 liters per minute

The rate at which the mixture is drained = 5 liters per minute

The amount of salt in the fish tank after t minutes = x

Where the volume of water with x grams of salt = 15 liters

dx =  (5·c - 5·c/3)×dt = 20/3·c = 6\frac{2}{3} \cdot c \cdot dt

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

b. The amount of salt, x after t minutes is given by the relation

\dfrac{dx}{dt} = 6\frac{2}{3} \cdot c

dx = 6\frac{2}{3} \cdot c \cdot dt

x(t) = \int\limits \, dx  = \int\limits \left ( 6\frac{2}{3} \cdot c \right) \cdot dt

x(t) = 6\frac{2}{3} \cdot c \cdot t

c. Given that in 10 minutes, the amount of salt in the tank = 25 grams, and the volume is 15 liters, we have;

x(10) = 25 \ grams(15 \ in \ liters) = 6\frac{2}{3} \times c \times 10

6\frac{2}{3} \times c  =\dfrac{25 \ grams }{10}

c  =\dfrac{25 \ g/L }{10 \times 6\frac{2}{3} }  = \dfrac{25 \ g/L}{10 \times \dfrac{20}{3} } =\dfrac{3}{200} \times 25 \ g/L= \dfrac{75}{200}  \ g/L = \dfrac{3}{8}  \ g/L

c  = \dfrac{3}{8}  \ g/L

4 0
3 years ago
Fine the value for the following <br><br>11 -12÷4+3 (6-2)<br><br>and<br><br>0÷21<br><br>​
MrRa [10]

Answer:

1. 20

2. 0

Step-by-step explanation:

1. 20

11 -12÷4+3 (6-2)

Brackets first

11-12÷4+3 x 4

Then division and multiplication

11-3+12

Subtraction next

8+12

Now addition

8+12=20

2. Anything divided by 0 is 0

4 0
3 years ago
Quadrilateral ABCD is a rectangle.
jeka94

Answer:

A

Step-by-step explanation:

The diagonals of a rectangle are congruent and bisect each other, so

AC = BD

2AG = 2DG, that is

AG = DG, substitute values

- 7y + 5 = 2y + 68 ( subtract 2y from both sides )

- 9y + 5 = 68 ( subtract 5 from both sides )

-9y = 63 ( divide both sides by - 9 )

y = - 7

Hence

BD = 2(2y + 68)

     = 4y + 136

     = (4 × - 7) + 136

     = - 28 + 136

     = 108 → A

5 0
3 years ago
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