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olya-2409 [2.1K]
3 years ago
10

If we fold a rectangular piece of paper in half multiple times and count the number of rectangles created, what type of sequence

are we creating? Write an explicit formula for this situation.​
Mathematics
2 answers:
Luda [366]3 years ago
8 0

Answer:

this and that, I ain't even gonna cap I don't know the answer  

Step-by-step explanation:

Serggg [28]3 years ago
3 0

Answer:

<h2>We are creating a geometric sequence because each time we fold, we double the number of rectangles.✍️✍️✍️</h2>

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(a) has no solutions.<br><br>(b) has infinitely many solutions.<br><br>(c) has exactly one solution.
grandymaker [24]

Answer and Step-by-step explanation:

Given

ax + by = c

qx + ry = s

(a) the equation has no solutions if a/q = b/r ≠ c/s, when this happens, we say the system of equations has no solution. For example

x + y = 3

x + y = 5

Subtracting first equation from the second we have:

0 = 2 which is impossible.

(b) the equations have infinite solutions if a/q = b/r = c/s, for example

x + y = 2

x + y = 2

Subtracting the first equation from the second we have

0 = 0, since this is always true, then it has infinite solutions.

(c) the equations have unique solutions if a/q ≠ b/r, for example

x + y = 2

x – y = 1

Adding the first and second equation we have

2x = 3, we can get x from here and definitely y, so we have just one solution.

6 0
3 years ago
Question 16 of 50
saul85 [17]
Equation:

y=6,000(1.05)^5

Answer:
7657
8 0
1 year ago
Every set of three points is coplanar. <br> a. True<br> b. False
Ket [755]
We know that 3 point can creating always a plane 

so from this result the right choice is A. so is true 
4 0
3 years ago
Im broke have this but like whats 24X58-9=<br><br><br><br> 800x24=?
Mekhanik [1.2K]

Answer:

24X58-9=1,383

800x24=19,200

Step-by-step explanation:

24x58=(24x8)+(24x50)

24x8=160+32=192

24x50=200+1,000=1,200

192+1,200=1,392-9=1,383

800x24=3,200+16,000=19,200

4 0
2 years ago
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strojnjashka [21]
1 3/9 but if reduce to lowest term than 1 1/3
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3 years ago
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