1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
nignag [31]
3 years ago
7

A phone sells for $700. It is now on sale for 1/5 off the

Mathematics
1 answer:
Leona [35]3 years ago
5 0

\text{Find how much she was discounted:}\\\\\text{We know that the base price of the phone is 700}\\\\\text{It's on sale for 1/5 of the price (20\%), so multiply 700 by 0.20 and subtract}\\\\700*0.20=140\\\\700-140=560\\\\\text{Now, we know that there's a 10\% discount off the sale price, so precede}\\\text{with the same steps}\\\\560*0.10=56\\\\560-56=504\\\\\text{To find total discount price, subtract 504 from the original price}\\\\700-504=196\\\\\boxed{\$196}

You might be interested in
The length of a rectangle is five times its width. The perimeter of the rectangle is at most 96 cm.
kupik [55]

answers B and D are clearly wrong and if u do some simple thinking you can determine the answer is C...


Have a fantabulous day! :)

5 0
3 years ago
Read 2 more answers
two functions a and b are described as follows function a: y=8x+3 function b:the rate of change is 1 and the y intercept is 4 ho
AnnZ [28]

Answer:

7

Step-by-step explanation:

rate of change of function not necessary mean linear, it can be the slope of a tangent line.

a: y=8x+3    slope = 8

b: rate of change: 1

8-1=7

I wish this is true...

3 0
3 years ago
Two similar solids have a scale factor of 6 : 7. What is the ratio of their volumes, expressed in lowest terms?
Anarel [89]
The ratio of volumes is equal to the ratio of the cubes of the scale factor. Thus,
Volume ratio:
6³ : 7³
216 : 343

7 0
4 years ago
Read 2 more answers
A see-saw is 25 feet long with a fulcrum in the middle of the board. If a 60 lb. child sits three feet from the fulcrum, what is
My name is Ann [436]

Answer:

14.4 lb

Step-by-step explanation:

In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.

The torque generated by the child is:

T1 = 60 * 3 = 180 lb*feet

So, the torque generated by the weight needs to be higher than T1 in order to lift the child.

The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.

So, we have that:

T2 = 180 = mass * 12.5

mass = 180/12.5 = 14.4 lb

So the lowest weight is 14.4 lb

4 0
4 years ago
Practice using experimental probability.
VLD [36.1K]
Hi there!

The answer would be B. The number 3 was rolled 5 times in 36 trials.

This shows that out of all 36 times the dice was rolled the number 3 faced upwards 5 times.

Hope this helps !
4 0
3 years ago
Read 2 more answers
Other questions:
  • V+9
    12·1 answer
  • I need help... the question is confusing
    10·1 answer
  • For X, (3x-40°)=2x-10°)​
    15·1 answer
  • A computer company charges a flat fee of $250 for the computer and extra charges for any add-ons. a customer orders a computer w
    13·1 answer
  • what is the first step used in solving this equation 2x+9y=28 and 3x-3y=14. Identify the variable that will be solved for when y
    8·1 answer
  • Find the length of Cable 1. <br> Find Cable 2 bridge span. <br> Find Length of Cable 2
    9·1 answer
  • A set of pens sells for $6.25 and costs $3.50 to make. Forty-two percent of the profit (the difference between the purchase pric
    11·2 answers
  • AC=3x+3, AB=-1+2x, and BC=11 find x
    8·1 answer
  • In a 24 marathon, solve the 24 puzzle given by the poster above you, and post a new 24 puzzle of your own!
    15·2 answers
  • Craig is practicing his baseball pitching he kept track of the speed oI made a histogram at right can you tell the speed of each
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!