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neonofarm [45]
2 years ago
14

The areas of two similar octagons are 9 m² and 25 m². What is the scale factor of their side lengths? PLZ HELP PLZ PLZ PLZ

Mathematics
1 answer:
torisob [31]2 years ago
6 0

Answer:

\frac{3}{5}

Step-by-step explanation:

Let the side length for the octagon having 9m² as area = x

Side length for the octagon having area of 25m² = y.

Thus:

\frac{9}{25} = (\frac{x}{y})^2 (area of similar polygons theorem)

The scale factor of their sides would be \frac{x}{y}. Which is:

\sqrt{\frac{9}{25}} = \frac{x}{y}

\frac{\sqrt{9}}{\sqrt{25}} = \frac{x}{y}

\frac{3}{5} = \frac{x}{y}

Scale factor of their sides = \frac{3}{5}

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The expression which represents the perimeter, in centimeters, of the rectangle is; (18d +10f) centimetres.

<h3>Perimeter of a rectangle</h3>

Since the perimeter of a rectangle is given by the formula;

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In essence, Perimeter, P = 2(2d – 3f) + 2(7d + 8f)

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Ultimately, the perimeter of the rectangle is; (18d +10f) centimetres.

Read more on perimeter of a rectangle;

brainly.com/question/17297081

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Answer:

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