Answer:
3 2/3 is the answer
Step-by-step explanation:
Conversion a mixed number 2 3/
4
to a improper fraction: 2 3/4 = 2 3/
4
= 2 · 4 + 3/
4
= 8 + 3/
4
= 11/
4
To find new numerator:
a) Multiply the whole number 2 by the denominator 4. Whole number 2 equally 2 * 4/
4
= 8/
4
b) Add the answer from previous step 8 to the numerator 3. New numerator is 8 + 3 = 11
c) Write a previous answer (new numerator 11) over the denominator 4.
Two and three quarters is eleven quarters
Divide: 11/
4
: 3/
4
= 11/
4
· 4/
3
= 11 · 4/
4 · 3
= 44/
12
= 4 · 11 /
4 · 3
= 11/
3
Dividing two fractions is the same as multiplying the first fraction by the reciprocal value of the second fraction. The first sub-step is to find the reciprocal (reverse the numerator and denominator, reciprocal of 3/
4
is 4/
3
) of the second fraction. Next, multiply the two numerators. Then, multiply the two denominators. In the next intermediate step , cancel by a common factor of 4 gives 11/
3
.
so you simplify to get 3 2/3
f(h(x))= 2x -21
Step-by-step explanation:
f(x)= x^3 - 6
h(x)=\sqrt[3]{2x-15}
WE need to find f(h(x)), use composition of functions
Plug in h(x)
f(h(x))=f(\sqrt[3]{2x-15})
Now we plug in f(x) in f(x)
f(h(x))=f(\sqrt[3]{2x-15})=(\sqrt[3]{2x-15})^3 - 6
cube and cube root will get cancelled
f(h(x))= 2x-15 -6= 2 x-21
To reduce the radical, you have to factorize 108.
108 is a multiple of 3, so to factorize it, you can divide it by 3
You can rewrite the square root as:
![\sqrt[]{3\cdot36}=\sqrt[]{3}\cdot\sqrt[]{36}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%5Ccdot36%7D%3D%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D)
The square root of 36 is equal to 6 so you can write the expression as:
![\sqrt[]{3}\cdot\sqrt[]{36}=6\sqrt[]{3}](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B3%7D%5Ccdot%5Csqrt%5B%5D%7B36%7D%3D6%5Csqrt%5B%5D%7B3%7D)
Answer:
The answer is C
Step-by-step explanation:
Multiply all of the values by 2 and then you end up with the bigger triangle.
Answer:
15( b+ a) - 2(a + 0 ) = c
then
c+b = t
We could put the two together to make 15(b+a)- 2(a+0) + b = t
Where t = 8379.70
a= £249.99 b= 329.99
Step-by-step explanation:
Equal amounts are 8549.7 from 30 mowers a+b = small and large.
If we use this as an even and take away a+b at different equations we can find the answer to be 8379.70 on the 2nd equation. First equation = 8579.70
8549.7- 249.99-249.99+329.99 to equal the given year to find c in first equation and total in year = t within the above equation.
