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seraphim [82]
3 years ago
6

Sue charges a flat rate of $20 plus $10 per hour it takes her to mow a lawn. Which equation shows the correct way to find the co

st y of mowing a lawn for x hours.
Mathematics
1 answer:
Nookie1986 [14]3 years ago
3 0

Answer:

y=20+10x

Step-by-step explanation:

From the information provided, the equation would indicate that the cost of mowing a lawn would be equal to the flat rate plus the result of multiplying the cost per hour for the number of hours:

y=20+10x, where:

y is the cost of mowing a lawn

x is the number of hours

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Strike441 [17]

Answer:

1) ASA

2) none

3) ASA

Step-by-step explanation:

In the first picture we have two angles and one included side of one triangle is congruent to corresponding two angles and one included side of another triangle, therefore by ASA postulate of congruence both triangles are congruent.

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Now, two corresponding angles and one included side (10 units) of both triangles are congruent  therefore by ASA postulate of congruence both triangles are congruent.

In the third picture, we have two triangle with one same vertex, then their vertical angles must be congruent.

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3 years ago
Find the value of x. Write your answer in simplest form.
katrin2010 [14]

Answer:

X=8

Step-by-step explanation:

(8 \sqrt{2} ) ^{2}  =  {x}^{2}  +  {x}^{2}  \\ 128 = 2 {x}^{2}  \\  {x}^{2}  =  \frac{128}{2}  \\  {x}^{2}  = 64 \\ x = 8

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3 years ago
Use the table to the right to answer the following question.
zepelin [54]

The energy is compared based on the information given below.

<h3>How to illustrate the energy?</h3>

Energy released by burning 1 kilogram of element A = EA = 5.1 * (10)8

Energy released by fission of hydrogen in 1 kilogram of element B = EB = 1.3 * (10)10

Therefore,

Ratio = EB / EA = 1.3 * (10)10 / 5.1 * (10)8 = 25

Thus, the fission of 1 kg of element B releases 25 times as much energy as burning 1 kilogram of element A.

Learn more about energy on:

brainly.com/question/13881533

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<u>The other part of the question:</u>

Energy released by burning 1 kilogram of element A = 5.1 times 10 Superscript 8

Energy released by the fission of hydrogen in 1 kilogram of element B = 1.3 times 10 Superscript 10

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seropon [69]

Answer:

A is the correct answer.

Hope this helps \mathtt{: )}

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